从数组中删除与特定字符串匹配的所有元素

Question

从数组中删除与特定字符串匹配的所有元素的最简单方法是什么？例如:

array = [1,2,'deleted',4,5,'deleted',6,7];

我想'deleted'从数组中删除所有.

Answer 1

只需使用Array.prototype.filter()函数来获取条件的元素

var array = [1,2,'deleted',4,5,'deleted',6,7];
var newarr = array.filter(function(a){return a !== 'deleted'})

更新:ES6语法

let array = [1,2,'deleted',4,5,'deleted',6,7]
let newarr = array.filter(a => a !== 'deleted')

Answer 2

如果要从主数组中删除多个字符串,可以尝试这样做

// Your main array 
var arr = [ '8','abc','b','c'];

// This array contains strings that needs to be removed from main array
var removeStr = [ 'abc' , '8'];

arr = arr.filter(function(val){
  return (removeStr.indexOf(val) == -1 ? true : false)
})

console.log(arr);

// 'arr' Outputs to :
[ 'b', 'c' ]

要么

更好的性能(使用哈希),如果不需要严格的类型相等

// Your main array 
var arr = [ '8','deleted','b','c'];

// This array contains strings that needs to be removed from main array
var removeStr = [ 'deleted' , '8'];
var removeObj = {};  // Use of hash will boost performance for larger arrays
removeStr.forEach( e => removeObj[e] = true);

var res = arr.filter(function(val){
  return !removeObj[val]
})

console.log(res);

// 'arr' Outputs to :
[ 'b', 'c' ]

Answer 3

array = array.filter(function(s) {
    return s !== 'deleted';
});

Answer 4

如果你想要相同的数组，那么你可以使用

var array = [1,2,'deleted',4,5,'deleted',6,7];
var index = "deleted";
for(var i = array.length - 1; i >= 0; i--) {
    if(array[i] === index) {
       array.splice(i, 1);
    }
}

例 1

否则，您可以使用Array.prototype.filter它创建一个新数组，其中包含通过提供的函数实现的测试的所有元素。

 var arrayVal = [1,2,'deleted',4,5,'deleted',6,7];
function filterVal(value) {
  return value !== 'deleted';
}
var filtered = arrayVal.filter(filterVal);

例2