poo*_*per 7 python printing inline dynamic
该字典对应于编号节点:
{0: True, 1: True, 2: True, 3: False, 4: False, 5: False, 6: True, 7: True, 8: False, 9: False}
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使用两个打印语句,我想打印标记和未标记的节点,如下所示:
标记节点: 0 1 2 6 7
未标记的节点: 3 4 5 8 9
我想要一些接近的东西:
print("Marked nodes: %d" key in markedDict if markedDict[key] = True)
print("Unmarked nodes: %d" key in markedDict if markedDict[key] = False)
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您可以使用列表推导:
nodes = {0: True, 1: True, 2: True,
3: False, 4: False, 5: False,
6: True, 7: True, 8: False, 9: False}
print("Marked nodes: ", *[i for i, value in nodes.items() if value])
print("Unmarked nodes: ", *[i for i, value in nodes.items() if not value])
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输出:
Marked nodes: 0 1 2 6 7
Unmarked nodes: 3 4 5 8 9
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