简单的SQL查询,结合结果和划分

pie*_*iet 9 mysql sql

我试图从2个表中得到2个计数计算出像MySQL数据库那样的百分比:

  1. select field_one, count(*) as COUNT_ONE from table1 group by field_one;

  2. select other_field,count(*) as COUNT_TWO from table2 group by other_field;

我想结合结果并FINAL_COUNT=(COUNT_ONE/COUNT_TWO) * 100保持百分比?

Fos*_*sco 17

又快又脏:

select (a.count_one / b.count_two) * 100 as final_count from 
(select field_one, count(*) as count_one from table1 group by field_one) a,
(select field_two, count(*) as count_two from table2 group by field_two) b
where a.field_one = b.field_two
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gab*_*886 5

select sum(((QUERY FROM TABLE 1) / (QUERY FROM TABLE 2)) * 100) as percentage
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  • 这个好吃!但FYI:你不需要`总和()`的代码,这就足以:`选择(((查询来自表1)/(查询从表2))*100)percentage` (2认同)