Tom*_*Tom 19 sql database sql-server
以下SQL根据它们的关系分隔表.问题在于在3000系列下排序的表格.作为外键的一部分并使用外键的表.任何人都有一些聪明的递归CTE或一个存储过程来进行必要的排序?程序连接到数据库不被视为解决方案.
编辑:我根据第一个解决方案在"答案"中发布了答案对于任何重新发布我自己的"正确"答案的人来说,免费"正确答案"!
WITH
AllTables(TableName) AS
(
SELECT OBJECT_SCHEMA_NAME(so.id) +'.'+ OBJECT_NAME(so.id)
FROM dbo.sysobjects so
INNER JOIN sys.all_columns ac ON
so.ID = ac.object_id
WHERE
so.type = 'U'
AND
ac.is_rowguidcol = 1
),
Relationships(ReferenceTableName, ReferenceColumnName, TableName, ColumnName) AS
(
SELECT
OBJECT_SCHEMA_NAME (fkey.referenced_object_id) + '.' +
OBJECT_NAME (fkey.referenced_object_id) AS ReferenceTableName
,COL_NAME(fcol.referenced_object_id,
fcol.referenced_column_id) AS ReferenceColumnName
,OBJECT_SCHEMA_NAME (fkey.parent_object_id) + '.' +
OBJECT_NAME(fkey.parent_object_id) AS TableName
,COL_NAME(fcol.parent_object_id, fcol.parent_column_id) AS ColumnName
FROM sys.foreign_keys AS fkey
INNER JOIN sys.foreign_key_columns AS fcol ON
fkey.OBJECT_ID = fcol.constraint_object_id
),
NotReferencedOrReferencing(TableName) AS
(
SELECT TableName FROM AllTables
EXCEPT
SELECT TableName FROM Relationships
EXCEPT
SELECT ReferenceTableName FROM Relationships
),
OnlyReferenced(Tablename) AS
(
SELECT ReferenceTableName FROM Relationships
EXCEPT
SELECT TableName FROM Relationships
),
-- These need to be sorted based on theire internal relationships
ReferencedAndReferencing(TableName, ReferenceTableName) AS
(
SELECT r1.Tablename, r2.ReferenceTableName FROM Relationships r1
INNER JOIN Relationships r2
ON r1.TableName = r2.ReferenceTableName
),
OnlyReferencing(TableName) AS
(
SELECT Tablename FROM Relationships
EXCEPT
SELECT ReferenceTablename FROM Relationships
)
SELECT TableName, 1000 AS Sorting FROM NotReferencedOrReferencing
UNION
SELECT TableName, 2000 AS Sorting FROM OnlyReferenced
UNION
SELECT TableName, 3000 AS Sorting FROM ReferencedAndReferencing
UNION
SELECT TableName, 4000 AS Sorting FROM OnlyReferencing
ORDER BY Sorting
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NTD*_*DLS 14
我的演绎中等调整:这个是SQL-2005 +,适用于没有"rowguidcol"的数据库:
WITH TablesCTE(SchemaName, TableName, TableID, Ordinal) AS
(
SELECT
OBJECT_SCHEMA_NAME(so.object_id) AS SchemaName,
OBJECT_NAME(so.object_id) AS TableName,
so.object_id AS TableID,
0 AS Ordinal
FROM
sys.objects AS so
WHERE
so.type = 'U'
AND so.is_ms_Shipped = 0
UNION ALL
SELECT
OBJECT_SCHEMA_NAME(so.object_id) AS SchemaName,
OBJECT_NAME(so.object_id) AS TableName,
so.object_id AS TableID,
tt.Ordinal + 1 AS Ordinal
FROM
sys.objects AS so
INNER JOIN sys.foreign_keys AS f
ON f.parent_object_id = so.object_id
AND f.parent_object_id != f.referenced_object_id
INNER JOIN TablesCTE AS tt
ON f.referenced_object_id = tt.TableID
WHERE
so.type = 'U'
AND so.is_ms_Shipped = 0
)
SELECT DISTINCT
t.Ordinal,
t.SchemaName,
t.TableName,
t.TableID
FROM
TablesCTE AS t
INNER JOIN
(
SELECT
itt.SchemaName as SchemaName,
itt.TableName as TableName,
itt.TableID as TableID,
Max(itt.Ordinal) as Ordinal
FROM
TablesCTE AS itt
GROUP BY
itt.SchemaName,
itt.TableName,
itt.TableID
) AS tt
ON t.TableID = tt.TableID
AND t.Ordinal = tt.Ordinal
ORDER BY
t.Ordinal,
t.TableName
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感谢您使用NXC的解决方案.你让我在正确的轨道上使用递归CTE来解决问题.
WITH
TablesCTE(TableName, TableID, Ordinal) AS
(
SELECT
OBJECT_SCHEMA_NAME(so.id) +'.'+ OBJECT_NAME(so.id) AS TableName,
so.id AS TableID,
0 AS Ordinal
FROM dbo.sysobjects so INNER JOIN sys.all_columns ac ON so.ID = ac.object_id
WHERE
so.type = 'U'
AND
ac.is_rowguidcol = 1
UNION ALL
SELECT
OBJECT_SCHEMA_NAME(so.id) +'.'+ OBJECT_NAME(so.id) AS TableName,
so.id AS TableID,
tt.Ordinal + 1 AS Ordinal
FROM
dbo.sysobjects so
INNER JOIN sys.all_columns ac ON so.ID = ac.object_id
INNER JOIN sys.foreign_keys f
ON (f.parent_object_id = so.id AND f.parent_object_id != f.referenced_object_id)
INNER JOIN TablesCTE tt ON f.referenced_object_id = tt.TableID
WHERE
so.type = 'U'
AND
ac.is_rowguidcol = 1
)
SELECT DISTINCT
t.Ordinal,
t.TableName
FROM TablesCTE t
INNER JOIN
(
SELECT
TableName as TableName,
Max (Ordinal) as Ordinal
FROM TablesCTE
GROUP BY TableName
) tt ON (t.TableName = tt.TableName AND t.Ordinal = tt.Ordinal)
ORDER BY t.Ordinal, t.TableName
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对于知道什么是可用的,我会用它来安全地清空数据库而不违反任何外键关系.(通过按降序截断)我还可以通过按升序填充表来安全地使用来自另一个数据库的数据填充表.