将JSONObject转换为Java对象

Ric*_*ard 8 java rest spring json jsonobject

我对服务进行了休息调用并将响应存储在一个JSONObject.但是,我试图将其转换为类对象并获得错误.这是我的代码:

RestOperations operations = /*initalize*/;
String body = /*build request body*/;
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
UserIdentifier userIdentifier = (UserIdentifier) jsonResponse.get("userIdentifier");
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这是响应的样子:

{
  "userIdentifier": {
    "uid": "ee63a52cda7bf411dd8603ac196951aa77",
    "code": "63a5297e7bf411dd8603ac196951aa77",
    "retailId": "860658787",
    "pointOfEntry": "RETAIL"
  },
  "resultCode": true
}
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以下是该UserIdentifier课程的样子:

public class UserIdentifier {
    private String uid;
    private String code;
    private String retailId;

    public UserIdentifier() {

    }

    public UserIdentifier(String uid, String code, String retailId) {
        this.uid = uid;
        this.code = code;
        this.retailId = retailId;
    }

    public String getuid() {
        return uid;
    }

    public void setuid(String uid) {
        this.uid = uid;
    }

    public String getcode() {
        return code;
    }

    public void setcode(String code) {
        this.code = code;
    }

    public String getretailId() {
        return retailId;
    }

    public void setretailId(String retailId) {
        this.retailId = retailId;
    }
}
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但我得到错误:

java.lang.ClassCastException: org.json.JSONObject cannot be cast to app.identity.UserIdentifier
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我究竟做错了什么?

编辑1:这是尝试从答案中使用gson:

Gson gson = new GsonBuilder().create();
String body = /*build request body*/;
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
UserIdentifier userIdentifier = gson.fromJson(jsonResponse.getString("userIdentifier"), UserIdentifier.class);
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但我得到错误:

org.json.JSONException: JSONObject["userIdentifier"] not a string.
    at org.json.JSONObject.getString(JSONObject.java:658) ~[json-20140107.jar:na]
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Mah*_*iri 8

你可能需要使用gson

   class Name{
String resultCode;
UserIdentifier useridentifier;
//getters

}

Gson gson=new Gson();
Name name=gson.fromJson(jsonString,Name.class);
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Ric*_*ard 5

找出问题所在.需要提取jsonobject而不是获取字符串.以下是解决问题的方法:

UserIdentifier userIdentifier = gson.fromJson(jsonResponse.getJSONObject("userIdentifier").toString(), UserIdentifier.class);
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