我不明白为什么你需要两个队列.我已经在这里和dupe线程中看到了答案,你只需要一个队列即可.
从欺骗线程来看,它有两个版本,一个优化推送,另一个优化pop.
推送优化:
push:
enqueue in queue
pop:
n = queue size.
dequeue an object, and enqueue it immediately after. Do this n - 1 times.
dequeue object, and return this.
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流行优化:
push:
enqueue in queue
n = queue size.
dequeue an object, and enqueue it immediately after. Do this n - 1 times.
pop:
dequeue from queue and return.
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然后,我不明白为什么你曾经想要这样做.责备你的教授让你浪费你的时间与无意义的编程问题.