Raj*_*Raj 7 rest spring json filter
我正在使用spring rest api 4.x. 我们需要根据请求参数过滤响应中的字段.
我的用户对象:
private class UserResource {
private String userLastName;
private String userFirstName;
private String email;
private String streetAddress;
}
E.g. URL: curl -i http://hostname:port/api/v1/users?fields=firstName,lastName.
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在这种情况下,我只需要返回请求参数"fields"中的字段.JSON输出应仅包含firstName,lastName.
有几种方法可以根据对象过滤Jackson中的字段.在我的情况下,我需要通过将字段列表传递给Jackson序列化程序来动态过滤.
请分享一些想法.
Raj*_*Raj 13
谢谢阿里.这是一个很大的帮助.让我今天实施它.我会发布结果
@JsonFilter("blah.my.UserEntity")
public class UserEntity implements Serializable {
//fields goes here
}
@RequestMapping(value = "/users", method = RequestMethod.GET, produces = MediaType.APPLICATION_JSON_VALUE)
public MappingJacksonValue getUsers(@RequestParam MultiValueMap<String, String> params) {
//Build pageable here
Page<UserEntity> users = userService.findAll(pageable);
MappingJacksonValue mappingJacksonValue = new MappingJacksonValue(users);
FilterProvider filters = new SimpleFilterProvider()
.addFilter("blah.my.UserEntity", SimpleBeanPropertyFilter
.filterOutAllExcept("userFirstName"));
mappingJacksonValue.setFilters(filters);
return mappingJacksonValue;
}
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使用 aResponseBodyAdvice可以在响应写入 HTTP 响应之前更改响应。在beforeBodyWrite(...)方法中,您可以访问当前的值ServerHttpRequest,您可以读取该fields值。您的身体建议如下:
@ControllerAdvice
public class MyResponseBodyAdvisor implements ResponseBodyAdvice<UserResource> {
@Override
public boolean supports(MethodParameter returnType, Class<? extends HttpMessageConverter<?>> converterType) {
return returnType.getParameterType().equals(UserResource.class);
}
@Override
public UserResource beforeBodyWrite(UserResource body, MethodParameter returnType, MediaType selectedContentType, Class<? extends HttpMessageConverter<?>> selectedConverterType, ServerHttpRequest request, ServerHttpResponse response) {
String fields = ((ServletServerHttpRequest) request).getServletRequest().getParameter("fields");
// body.set...(null) for each field not in fields
return body;
}
}
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