使用django频道时如何使用Channel而不是Group？

Question

我正试图在django上使用渠道项目(http://channels.readthedocs.org/en/latest/index.html).

虽然在文档上有一个很好的教程,用于构建基于Group的websocket应用程序(聊天),我找不到与客户特定的简单推送机制相关的东西(所以不需要使用Group)

假设我想要与各种新闻提供者一起构建一个feed聚合器,当用户访问主页并等待所有的feed被解析时,我想向他发送关于服务器正在解析哪一个的信息性消息,而他等待.

我现在得到的是:consumers.py

from channels import Group, Channel
from .views import sort_articles_by_date
from .soup import ProviderParser
from .models import Provider


# Connected to websocket.connect and websocket.keepalive
def ws_add(message):
    Group("news_providers_loading").add(message.reply_channel)

def ws_message(message):
    providers = Provider.objects.all()

    articles = []
    for provider in providers:
        Group("news_providers_loading").send({'content': str(provider)})
        parser = ProviderParser(provider)
        articles.extend(parser.parse_articles())

     sort_articles_by_date(articles)


 # Connected to websocket.disconnect
 def ws_disconnect(message):
     Group("news_providers_loading").discard(message.reply_channel)

routing.py

channel_routing = {
    "websocket.connect": "news_providers.consumers.ws_add",
    "websocket.keepalive": "news_providers.consumers.ws_add",
    "websocket.receive": "news_providers.consumers.ws_message",
    "websocket.disconnect": "news_providers.consumers.ws_disconnect",
}

虽然它工作正常,但我觉得这有点矫枉过正(？)有没有办法只使用Channel构造函数而不是Group？

谢谢 :)

Answer 1

更新:

渠道版本= 0.9

现在通道为0.9,因此客户端需要进行一些更改才能从服务器接收消息:

class Content:
    def __init__(self, reply_channel):
        self.reply_channel = reply_channel

    def send(self, json):
        self.reply_channel.send({
            'reply_channel': str(self.reply_channel),
            'text': dumps(json)
        })


def ws_message(message):
    content = Content(message.reply_channel)
    content.send({'hello': 'world'})

routing.py保持不变......

渠道版本<0.9

呸,有点棘手,但发现了它.

您必须使用消息的reply_channel属性.所以这:

Group("news_providers_loading").send({'content': str(provider)})

变成这样:

Channel(message.reply_channel).send({'content': str(provider)})

我现在得到的是:

from channels import Channel
from .soup import ProviderParser, sort_articles_by_date
from .models import Provider
from django.template.loader import render_to_string
from json import dumps


class Content:
    def __init__(self, reply_channel):
        self.reply_channel = reply_channel

    def send(self, json):
        Channel(self.reply_channel).send({'content': dumps(json)})


def ws_message(message):
    providers = Provider.objects.all()
    content = Content(message.reply_channel)

    content.send({'providers_length': len(providers)})

    articles = []
    for provider in providers:

        content.send({'provider': str(provider)})

        parser = ProviderParser(provider)
        articles.extend(parser.parse_articles())

    sort_articles_by_date(articles)
    html = render_to_string('news_providers/article.html', {'articles': articles})

    content.send({'html': html})

routing.py

channel_routing = {
     "websocket.receive": "news_providers.consumers.ws_message",
}

虽然您可能希望保持连接,保持连接和断开连接方法(简单的foo方法),但似乎并不完全确定 - !

# connect, keepalive and disconnect
def ws_foo(message):
    pass

routing.py

channel_routing = {
    "websocket.connect": "news_providers.consumers.ws_foo",
    "websocket.keepalive": "news_providers.consumers.ws_foo",
    "websocket.receive": "news_providers.consumers.ws_message",
    "websocket.disconnect": "news_providers.consumers.ws_foo",
}