Azu*_*iva 1 c# arrays jagged-arrays
我的函数应该用"&"";"分割字符串 和","并返回三个锯齿状阵列,反之亦然.(来自以下数据:1,2,3; 4,5,6和1,2,3; 4,5,6)
我一直在努力使它工作,现在由于某种原因我得到一个system.argumentnullexception on
Array.Copy(playerOneEnts, allEnts[0], playerOneEnts.Length);
Array.Copy(playerTwoEnts, allEnts[1], playerTwoEnts.Length);
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完整代码:
public string convertToString(string[][][] allEnts)
{
string Player = string.Empty;
string[][] playerOneEnts = new string[maxEnts][];
string[][] playerTwoEnts = new string[maxEnts][];
Array.Copy(allEnts[0], playerOneEnts, allEnts[0].Length);
Array.Copy(allEnts[1], playerTwoEnts, allEnts[1].Length);
for (int j = 0; j < playerOneEnts.Length; j++)
{
for (int i = 0; i < playerOneEnts[j].Length; i++)
{
Player += playerOneEnts[j][i] + ",";
}
Player = Player.TrimEnd(',');
Player += ";";
}
Player = Player.TrimEnd(';');
Player += "&";
for (int j = 0; j < playerTwoEnts.Length; j++)
{
for (int i = 0; i < playerTwoEnts[j].Length; i++)
{
Player += playerTwoEnts[j][i] + ",";
}
Player = Player.TrimEnd(',');
Player += ";";
}
Player = Player.TrimEnd(';');
return Player;
}
public string[][][] convertToArray(string ents)
{
string[] p = new string[2];
string[][] playerOneEnts = new string[maxEnts][];
string[][] playerTwoEnts = new string[maxEnts][];
string[][][] allEnts = new string[2][][];
p = ents.Split('&');
try
{
playerOneEnts = p[0].Split(new[] { ";" }, StringSplitOptions.RemoveEmptyEntries).Select(chunk => chunk.Split(',')).ToArray();
playerTwoEnts = p[1].Split(new[] { ";" }, StringSplitOptions.RemoveEmptyEntries).Select(chunk => chunk.Split(',')).ToArray();
MessageBox.Show(playerOneEnts.Length.ToString());
Array.Copy(playerOneEnts, allEnts[0], playerOneEnts.Length);
Array.Copy(playerTwoEnts, allEnts[1], playerTwoEnts.Length);
}
catch
{
MessageBox.Show("unable to convert string", "Fatal Error");
}
return allEnts;
}
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代码看起来像一场灾难给我,如果有人知道这个转换为字符串我很乐意为任何想法更好的方式.摆脱我的错误已经足够帮助我了.
谢谢!
以下是使用Linq的示例(需要.Net 4.0):
var source = "1,2,3;4,5,6&1,2,3;4,5,6";
string[][][] decoded = source.Split('&').Select(x => x.Split(';').Select(y => y.Split(',').ToArray()).ToArray()).ToArray();
string reencoded = String.Join("&", decoded.Select(x => String.Join(";", x.Select(y => String.Join(",", y)))));
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或者,IEnumarable泛型可用于避免转换为数组.
警告:此代码不验证输入,例如数组长度.
编辑: .NET 3.5的重编码器:
var reencoded = String.Join("&", decoded.Select(x => String.Join(";", x.Select(y => String.Join(",", y)).ToArray())).ToArray());
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