Fli*_*ats 5 javascript css jquery angularjs
jsfiddle:https://jsfiddle.net/Flignats/jzrzo56u/3/
我的页面上有一个最初隐藏的元素(popover).当页面上的另一个元素悬停时,我希望弹出框显示在光标旁边.
在我的小提琴中,我有3个段落和弹出窗口.当用户的光标输入段落时,将显示弹出框.当用户的光标离开元素时,不再显示弹出框.
我无法检索光标坐标并将光标位于光标附近.
任何帮助表示赞赏:)
角度代码:
var app = angular.module('myApp', []);
app.controller('Ctrl',['$scope',function($scope) {
$scope.name = 'Ray';
$scope.popover = false;
//Method to show popover
$scope.showPopover = function() {
return $scope.popover = !$scope.popover;
};
}]);
Run Code Online (Sandbox Code Playgroud)
HTML代码:
<div ng-app="myApp" ng-controller="Ctrl">
<div id="container">
<p ng-mouseenter="showPopover()" ng-mouseleave="showPopover()">Square 1</p>
<p ng-mouseenter="showPopover()" ng-mouseleave="showPopover()">Square 2</p>
<p ng-mouseenter="showPopover()" ng-mouseleave="showPopover()">Square 3</p>
</div>
<div class="pop-availability" ng-show="popover">
<div class="pop-title">
<p>Title Content Goes Here</p>
</div>
<div class="pop-content">
<table class="pop-table">
<thead>
<tr>
<th></th>
<th ng-repeat='name in data.record'>{{name.name}}</th>
</tr>
</thead>
<tbody>
<tr>
<td>Row 1</td>
<td ng-repeat='available in data.record'>{{available.number}}</td>
</tr>
<tr>
<td>Row 2</td>
<td ng-repeat='unavailable in data.record'>{{unavailable.number}}</td>
</tr>
<tr>
<td>Row 3</td>
<td ng-repeat='unassigned in data.record'>{{unassigned.number}}</td>
</tr>
</tbody>
</table>
</div>
</div>
</div>
Run Code Online (Sandbox Code Playgroud)
编辑:更新了捕获鼠标坐标的jsfiddle.仍然无法让popover移动到光标:https://jsfiddle.net/Flignats/jzrzo56u/4/
编辑:越来越近,但它是一个小小的车!https://jsfiddle.net/Flignats/jzrzo56u/5/
HTML - 将 $event 参数添加到 showPopover 函数
<p ng-mouseenter="showPopover($event)" ng-mouseleave="showPopover()">Square 1</p>
<p ng-mouseenter="showPopover($event)" ng-mouseleave="showPopover()">Square 2</p>
<p ng-mouseenter="showPopover($event)" ng-mouseleave="showPopover()">Square 3</p>
Run Code Online (Sandbox Code Playgroud)
并且使用 ng-style 你可以改变Source的位置
<div class="pop-availability" ng-show="popover"
ng-style="{left:field.left,
top:field.top}" >
Run Code Online (Sandbox Code Playgroud)
JavaScript
//Method to show popover
$scope.showPopover = function(mouseEvent) {
if (!mouseEvent)
{
mouseEvent = window.event;
}
$scope.field.left = mouseEvent.pageX + 'px';
$scope.field.top = mouseEvent.pageY+ 'px';
return $scope.popover = !$scope.popover;
};
Run Code Online (Sandbox Code Playgroud)
CSS 更改 - 添加position:absolute
.pop-availability {
border-radius: 8px;
box-shadow: 0 0 10px 0 #969696;
display: inline-block;
min-width: 375px;
position:absolute;
}
Run Code Online (Sandbox Code Playgroud)