如何在django-rest-swagger中指定查询参数序列化程序？

Question

我正在使用Django REST Framework和django-rest-swagger为我的API创建可浏览的界面.我可以使用YAML docstring指定请求正文序列化程序,但我还没有找到为请求查询参数指定序列化程序的方法.我使用的视图很像:

class ListBans(BaseBanView):

    def get(self, request):
        """
        List all profile bans
        ---
        response_serializer: backend_serializers.BanSerializer
        request_serializer: moderator_serializers.ListBansSerializer
        """
        serializer = moderator_serializers.ListBansSerializer(data=request.query_params)
        if serializer.is_valid(raise_exception=True):
            # query profile bans
            data = []
            return APIResponse(status=status.HTTP_200_OK, data=data)

class ListBansSerializer(serializers.Serializer):
    limit = serializers.IntegerField(default=10, help_text='query limit')
    offset = serializers.IntegerField(default=0, help_text='query offset')

我想要实现的是django-rest-swagger为查询参数创建表单字段,ListBansSerializer以便我不必parameters在docstring中手动指定该部分.有没有办法做到这一点？

Answer 1

我创建了一个简单的装饰器，该装饰器自动将查询参数附加到文档字符串中。源码可以在github上找到。这是一个用法示例：

class ListBansSerializer(serializers.Serializer):
    limit = serializers.IntegerField(default=10, help_text='query limit')
    offset = serializers.IntegerField(default=0, help_text='query offset')


class ListBans(BaseBanView):
    @add_query_parameters(ListBansSerializer)
    def get(self, request):
        """
        List all profile bans
        ---
        response_serializer: backend_serializers.BanSerializer
        """
        serializer = moderator_serializers.ListBansSerializer(data=request.query_params)
        if serializer.is_valid(raise_exception=True):
            # query profile bans
            data = []
            return APIResponse(status=status.HTTP_200_OK, data=data)