在使用文化信息时,将数字转换为double时,我遇到了奇怪的行为.使用荷兰文化进行
转换时"3,3",处理正确.如果我"3,3"使用美国文化转换,它会返回33.我期待一个错误.看我的例子:
static void Main(string[] args)
{
CultureInfo cultureDutch = new CultureInfo("nl-NL");
CultureInfo cultureUS = new CultureInfo("en-US");
System.Threading.Thread.CurrentThread.CurrentCulture = cultureDutch;
Console.WriteLine("Input 3,3 --> Expected 3,3");
Console.WriteLine("Output = " + Convert.ToDouble("3,3", cultureDutch));
// Actual result --> 3,3
Console.WriteLine("Input 3,3 --> Expected InvalidCastException");
Console.WriteLine("Output = " + Convert.ToDouble("3,3", cultureUS));
// Actual result --> 33
Console.WriteLine();
Console.WriteLine();
System.Threading.Thread.CurrentThread.CurrentCulture = cultureUS;
Console.WriteLine("Input 3.3 --> Expected InvalidCastException");
Console.WriteLine("Output = " + Convert.ToDouble("3.3", cultureDutch));
// Actual result --> 33
Console.WriteLine("Input 3.3 --> Expected 3.3");
Console.WriteLine("Output = " + Convert.ToDouble("3.3", cultureUS));
// Actual result --> 3.3
Console.ReadLine();
}
Run Code Online (Sandbox Code Playgroud)
处理这个问题的正确方法是什么?当小数(或千位)分隔符无效时,我更喜欢异常.
结合 Boas Enkler 的回答,我已经能够解决这个问题。因此,首先我将根据当前文化扫描输入中的千位分隔符。最后,我将把输入值解析为双精度值。
private static string RemoveThousandSeparator(string input)
{
Regex removeThousandSeparatorExpr = new Regex(@"^-?(?:\d+|\d{1,3}(?:\"
+ <CultureInfo>.NumberGroupSeparator + @"\d{3})+)(?:\"
+ <CultureInfo>.NumberDecimalSeparator + @"\d+)?$");
Match match = removeThousandSeparatorExpr.Match(input);
if (match.Success)
{
input = input.Replace(<CultureInfo>.NumberGroupSeparator, "");
}
else
{
throw new Exception("Invalid input value");
}
return input;
}
Run Code Online (Sandbox Code Playgroud)