我已经在几何方面取得了一些进展,我正在整理整个场景.该场景有几十个对象,每个对象由一个边界立方体定义,其边角由两个SCNVector3指定(最初是两组x,y,z).
这是我到目前为止所拥有的一个例子 - 它是一个11元素的对数周期天线,就像70年代的旧式电视天线一样.每条灰线是"元件",通常由铝棒制成.我使用了从+ ve到-ve Y的SCNCylinders,整个东西不到100行(SK非常棒).
如果元素在X上不对称并且因此必须旋转SCNCylinder,则会出现问题.我找到了这个例子,但是我无法理解具体细节......它似乎利用了一个球体是对称的这一事实,所以角度有点"消失".
有没有人有一个通用的功能,它将采取两个3D点并返回适合设置节点的eulerAngle的SCNVector3,或类似的解决方案?
Win*_*ill 19
上面提到的两种解决方案都运行良好,我可以为这个问题提供第三种解决方案
//extension code starts
func normalizeVector(_ iv: SCNVector3) -> SCNVector3 {
let length = sqrt(iv.x * iv.x + iv.y * iv.y + iv.z * iv.z)
if length == 0 {
return SCNVector3(0.0, 0.0, 0.0)
}
return SCNVector3( iv.x / length, iv.y / length, iv.z / length)
}
extension SCNNode {
func buildLineInTwoPointsWithRotation(from startPoint: SCNVector3,
to endPoint: SCNVector3,
radius: CGFloat,
color: UIColor) -> SCNNode {
let w = SCNVector3(x: endPoint.x-startPoint.x,
y: endPoint.y-startPoint.y,
z: endPoint.z-startPoint.z)
let l = CGFloat(sqrt(w.x * w.x + w.y * w.y + w.z * w.z))
if l == 0.0 {
// two points together.
let sphere = SCNSphere(radius: radius)
sphere.firstMaterial?.diffuse.contents = color
self.geometry = sphere
self.position = startPoint
return self
}
let cyl = SCNCylinder(radius: radius, height: l)
cyl.firstMaterial?.diffuse.contents = color
self.geometry = cyl
//original vector of cylinder above 0,0,0
let ov = SCNVector3(0, l/2.0,0)
//target vector, in new coordination
let nv = SCNVector3((endPoint.x - startPoint.x)/2.0, (endPoint.y - startPoint.y)/2.0,
(endPoint.z-startPoint.z)/2.0)
// axis between two vector
let av = SCNVector3( (ov.x + nv.x)/2.0, (ov.y+nv.y)/2.0, (ov.z+nv.z)/2.0)
//normalized axis vector
let av_normalized = normalizeVector(av)
let q0 = Float(0.0) //cos(angel/2), angle is always 180 or M_PI
let q1 = Float(av_normalized.x) // x' * sin(angle/2)
let q2 = Float(av_normalized.y) // y' * sin(angle/2)
let q3 = Float(av_normalized.z) // z' * sin(angle/2)
let r_m11 = q0 * q0 + q1 * q1 - q2 * q2 - q3 * q3
let r_m12 = 2 * q1 * q2 + 2 * q0 * q3
let r_m13 = 2 * q1 * q3 - 2 * q0 * q2
let r_m21 = 2 * q1 * q2 - 2 * q0 * q3
let r_m22 = q0 * q0 - q1 * q1 + q2 * q2 - q3 * q3
let r_m23 = 2 * q2 * q3 + 2 * q0 * q1
let r_m31 = 2 * q1 * q3 + 2 * q0 * q2
let r_m32 = 2 * q2 * q3 - 2 * q0 * q1
let r_m33 = q0 * q0 - q1 * q1 - q2 * q2 + q3 * q3
self.transform.m11 = r_m11
self.transform.m12 = r_m12
self.transform.m13 = r_m13
self.transform.m14 = 0.0
self.transform.m21 = r_m21
self.transform.m22 = r_m22
self.transform.m23 = r_m23
self.transform.m24 = 0.0
self.transform.m31 = r_m31
self.transform.m32 = r_m32
self.transform.m33 = r_m33
self.transform.m34 = 0.0
self.transform.m41 = (startPoint.x + endPoint.x) / 2.0
self.transform.m42 = (startPoint.y + endPoint.y) / 2.0
self.transform.m43 = (startPoint.z + endPoint.z) / 2.0
self.transform.m44 = 1.0
return self
}
}
//extension ended.
//in your code, you can like this.
let twoPointsNode1 = SCNNode()
scene.rootNode.addChildNode(twoPointsNode1.buildLineInTwoPointsWithRotation(
from: SCNVector3(1,-1,3), to: SCNVector3( 7,11,7), radius: 0.2, color: .cyan))
//end
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你可以参考http://danceswithcode.net/engineeringnotes/quaternions/quaternions.html
顺便说一下,当你使用圆柱体从3种方法中的两点之间划线时,你会得到相同的结果.但实际上,它们会有不同的正常线条.换句话说,如果你在两点之间使用盒子,盒子的两侧除了顶部和底部之外,将面向与上述3种方法不同的方向.
如果您需要进一步解释,请告诉我.
编辑:低于或等于IOS 11
我给你带来了好消息!你可以链接两个点并在这个Vector上放一个SCNNode!
拿这个,享受两点之间的画线!
class CylinderLine: SCNNode
{
init( parent: SCNNode,//Needed to add destination point of your line
v1: SCNVector3,//source
v2: SCNVector3,//destination
radius: CGFloat,//somes option for the cylinder
radSegmentCount: Int, //other option
color: UIColor )// color of your node object
{
super.init()
//Calcul the height of our line
let height = v1.distance(v2)
//set position to v1 coordonate
position = v1
//Create the second node to draw direction vector
let nodeV2 = SCNNode()
//define his position
nodeV2.position = v2
//add it to parent
parent.addChildNode(nodeV2)
//Align Z axis
let zAlign = SCNNode()
zAlign.eulerAngles.x = Float(M_PI_2)
//create our cylinder
let cyl = SCNCylinder(radius: radius, height: CGFloat(height))
cyl.radialSegmentCount = radSegmentCount
cyl.firstMaterial?.diffuse.contents = color
//Create node with cylinder
let nodeCyl = SCNNode(geometry: cyl )
nodeCyl.position.y = -height/2
zAlign.addChildNode(nodeCyl)
//Add it to child
addChildNode(zAlign)
//set contrainte direction to our vector
constraints = [SCNLookAtConstraint(target: nodeV2)]
}
override init() {
super.init()
}
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
}
}
private extension SCNVector3{
func distance(receiver:SCNVector3) -> Float{
let xd = receiver.x - self.x
let yd = receiver.y - self.y
let zd = receiver.z - self.z
let distance = Float(sqrt(xd * xd + yd * yd + zd * zd))
if (distance < 0){
return (distance * -1)
} else {
return (distance)
}
}
}
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@maury-markowitz 的回答对我有用,这是它的最新 (Swift4) 版本。对于使用SCNVector3Swift工作的任何人,我只能建议+-*/在您的代码中的某处添加运算符重载(例如从这里)。
extension SCNNode {
static func lineNode(from: SCNVector3, to: SCNVector3, radius: CGFloat = 0.25) -> SCNNode {
let vector = to - from
let height = vector.length()
let cylinder = SCNCylinder(radius: radius, height: CGFloat(height))
cylinder.radialSegmentCount = 4
let node = SCNNode(geometry: cylinder)
node.position = (to + from) / 2
node.eulerAngles = SCNVector3.lineEulerAngles(vector: vector)
return node
}
}
extension SCNVector3 {
static func lineEulerAngles(vector: SCNVector3) -> SCNVector3 {
let height = vector.length()
let lxz = sqrtf(vector.x * vector.x + vector.z * vector.z)
let pitchB = vector.y < 0 ? Float.pi - asinf(lxz/height) : asinf(lxz/height)
let pitch = vector.z == 0 ? pitchB : sign(vector.z) * pitchB
var yaw: Float = 0
if vector.x != 0 || vector.z != 0 {
let inner = vector.x / (height * sinf(pitch))
if inner > 1 || inner < -1 {
yaw = Float.pi / 2
} else {
yaw = asinf(inner)
}
}
return SCNVector3(CGFloat(pitch), CGFloat(yaw), 0)
}
}
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