当我在Racket中打印时,只打印结构类型,而不是值.(我在DrRacket工作,在互动区.)
例如,我有一个树结构:
#lang racket
(define-struct node [name left right])
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一个例子可能是:
(define SALLY (make-node 'sally BOBBY SUSIE))
(define BOBBY (make-node 'bobby NONE NONE))
(define SUSIE (make-node 'susie NONE NONE))
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我所看到的:
> (print SALLY)
#<node>
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我想看到的:
> (print SALLY)
(make-node 'sally (make-node 'bobby NONE NONE)
(make-node 'susie NONE NONE))
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我怎样才能看到价值而不是类型?
(define-struct node [name left right] #:transparent)
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> (define-struct node [name left right] #:transparent)
> (define NONE '())
> (define BOBBY (make-node 'bobby NONE NONE))
> (define SUSIE (make-node 'susie NONE NONE))
> (define SALLY (make-node 'sally BOBBY SUSIE))
> (print SALLY)
(node 'sally (node 'bobby '() '()) (node 'susie '() '()))
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注意:今天struct是首选,define-struct所以我已经编写了代码struct.
它并不真正打印类型,但它是对象的默认表示.您可以选择两种方法:
1.使用#:transparent关键字.
(struct node [name left right] #:transparent)
(define root (node 'd
(node 'b (node 'a '() '())
(node 'c '() '()))
(node 'f (node 'e '() '())
(node 'g '() '()))))
root ; ==>
; (node 'd
; (node 'b (node 'a '() '())
; (node 'c '() '()))
; (node 'f (node 'e '() '())
; (node 'g '() '()))))
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请注意它们看起来像建筑物?
1.为对象添加编写器
(struct node [name left right]
#:methods gen:custom-write
[;; needs to be named write-proc
(define (write-proc x port mode)
((if (eq? mode #t) write display) (fancy-writer x 0) port))
;; helper used by write-proc
(define (fancy-writer x ident)
(if (null? x)
""
(let ([new-ident (+ 5 ident)])
(string-append (fancy-writer (node-left x) new-ident)
(string-append (make-string ident #\space)
(symbol->string (node-name x))
"\n")
(fancy-writer (node-right x) new-ident)))))])
root ; ==>
; a
; b
; c
; d
; e
; f
; g
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