我有一个大型数据框(1616610行,255列),我需要根据一个键将每列的唯一值粘贴在一起.
例如:
> data = data.frame(a=c(1,1,1,2,2,3),
b=c("apples", "oranges", "apples", "apples", "apples", "grapefruit"),
c=c(12, 22, 22, 45, 67, 28),
d=c("Monday", "Monday", "Monday", "Tuesday", "Wednesday", "Tuesday"))
> data
a b c d
1 1 apples 12 Monday
2 1 oranges 22 Monday
3 1 apples 22 Monday
4 2 apples 45 Tuesday
5 2 apples 67 Wednesday
6 3 grapefruit 28 Tuesday
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我需要的是聚合255列中每一列中的每个唯一值,并为每个唯一值返回一个带逗号分隔符的新数据框.像这样:
a b c d
1 1 apples, oranges 12, 22 Monday
2 2 apples 45, 67 Tuesday, Wednesday
3 3 grapefruit 28 Thursday
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我尝试过使用aggregate,像这样:
output <- aggregate(data, by=list(data$a), paste, collapse=", ")
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但是对于这样大小的数据框,它过于耗费时间(数小时),而且我经常需要一起杀死这个过程.最重要的是,这将汇总所有值,而不仅仅是唯一值.有没有人有任何提示:
1)如何改善大数据集的聚合时间
2)然后获得每个字段的唯一值
顺便说一下,这是我关于SO的第一篇文章,感谢您的耐心等待.
移出评论:
library(data.table)
dt <- as.data.table(data)
dt[, lapply(.SD, function(x) toString(unique(x))), by = a]
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赠送:
a b c d
1: 1 apples, oranges 12, 22 Monday
2: 2 apples 45, 67 Tuesday, Wednesday
3: 3 grapefruit 28 Tuesday
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您可以执行以下操作dplyr
编辑1
\n更新的答案消除了使用引起的弃用警告summarise_each(从 dplyr 0.7.0 开始)。这使用summarise&across而不是summarise_each。
library(dplyr)\n\nfunc_paste <- function(x) paste(unique(x), collapse = ', ')\ndata %>%\n group_by(a) %>%\n summarise(across(everything(), func_paste))\n\n# Without "func_paste", using paste directly (from Alistaire's comment).\ndata %>%\n group_by(a) %>%\n summarise(across(everything(), ~ paste(unique(.), collapse = ', ')))\n\n## # A tibble: 3 \xc3\x97 4\n## a b c d\n## <dbl> <chr> <chr> <chr>\n## 1 1 apples, oranges 12, 22 Monday\n## 2 2 apples 45, 67 Tuesday, Wednesday\n## 3 3 grapefruit 28 Tuesday\nRun Code Online (Sandbox Code Playgroud)\n先前的答案,这将导致不推荐使用的警告(从 dplyr 0.7.0 开始)
\nfunc_paste <- function(x) paste(unique(x), collapse = ', ')\ndata %>%\n group_by(a) %>%\n summarise_each(funs(func_paste))\n\n## a b c d\n## (dbl) (chr) (chr) (chr)\n##1 1 apples, oranges 12, 22 Monday\n##2 2 apples 45, 67 Tuesday, Wednesday\n##3 3 grapefruit 28 Tuesday\n\n# Without "func_paste", using paste directly (from Alistaire's comment).\ndata %>%\n group_by(a) %>%\n summarise_each(funs(paste(unique(.), collapse = ', ')))\nRun Code Online (Sandbox Code Playgroud)\n