Paypal Sandbox API:javax.net.ssl.SSLHandshakeException:收到致命警报:handshake_failure

Question

我PayPal MassPay API在沙盒模式下使用时遇到异常.

相同的代码早先工作,现在它给了我一个SSLHandshakeException.我认为这是因为PayPal最新的SSL认证更新.有人可以帮我解决这个问题吗？

以下是我的异常日志:

http-bio-9090-exec-1, READ: TLSv1 Alert, length = 2
http-bio-9090-exec-1, RECV TLSv1 ALERT:  fatal, handshake_failure
http-bio-9090-exec-1, called closeSocket()
http-bio-9090-exec-1, handling exception: javax.net.ssl.SSLHandshakeException: Received fatal alert: handshake_failure
com.paypal.core.rest.PayPalRESTException: Received fatal alert: handshake_failure
    at com.paypal.core.rest.PayPalResource.execute(PayPalResource.java:374)
    at com.paypal.core.rest.PayPalResource.configureAndExecute(PayPalResource.java:225)
    at com.paypal.sdk.openidconnect.Tokeninfo.createFromAuthorizationCode(Tokeninfo.java:245)
    at com.oldwallet.controllers.CouponPaymentController.redeemed(CouponPaymentController.java:321)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:606)
    at org.springframework.web.method.support.InvocableHandlerMethod.invoke(InvocableHandlerMethod.java:215)
    at org.springframework.web.method.support.InvocableHandlerMethod.invokeForRequest(InvocableHandlerMethod.java:132)
    at org.springframework.web.servlet.mvc.method.annotation.ServletInvocableHandlerMethod.invokeAndHandle(ServletInvocableHandlerMethod.java:104)
    at org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter.invokeHandleMethod(RequestMappingHandlerAdapter.java:745)
    at org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter.handleInternal(RequestMappingHandlerAdapter.java:686)
    at org.springframework.web.servlet.mvc.method.AbstractHandlerMethodAdapter.handle(AbstractHandlerMethodAdapter.java:80)
    at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:925)
    at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:856)
    at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:953)
    at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:844)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
    at org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:829)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99)
    at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
    at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1008)
    at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:589)
    at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
    at java.lang.Thread.run(Thread.java:745)
Caused by: javax.net.ssl.SSLHandshakeException: Received fatal alert: handshake_failure
    at sun.security.ssl.Alerts.getSSLException(Alerts.java:192)
    at sun.security.ssl.Alerts.getSSLException(Alerts.java:154)
    at sun.security.ssl.SSLSocketImpl.recvAlert(SSLSocketImpl.java:1959)
    at sun.security.ssl.SSLSocketImpl.readRecord(SSLSocketImpl.java:1077)
    at sun.security.ssl.SSLSocketImpl.performInitialHandshake(SSLSocketImpl.java:1312)
    at sun.security.ssl.SSLSocketImpl.startHandshake(SSLSocketImpl.java:1339)
    at sun.security.ssl.SSLSocketImpl.startHandshake(SSLSocketImpl.java:1323)
    at sun.net.www.protocol.https.HttpsClient.afterConnect(HttpsClient.java:563)
    at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.connect(AbstractDelegateHttpsURLConnection.java:185)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1300)
    at java.net.HttpURLConnection.getResponseCode(HttpURLConnection.java:468)
    at sun.net.www.protocol.https.HttpsURLConnectionImpl.getResponseCode(HttpsURLConnectionImpl.java:338)
    at com.paypal.core.HttpConnection.execute(HttpConnection.java:93)
    at com.paypal.core.rest.PayPalResource.execute(PayPalResource.java:367)
    ... 36 more

Answer 1

问题是PayPal最近(1月19日或20日)将沙箱切换到TLS 1.2并且不再支持TLS 1.我猜你是在Java SE 7或更早版本上运行的.如果您在网上搜索一下,您会发现:

虽然Java SE 7发行版中的SunJSSE支持TLS 1.1和TLS 1.2,但默认情况下不会为客户端连接启用任何版本.某些服务器无法正确实现前向兼容性,并拒绝与TLS 1.1或TLS 1.2客户端通信.对于互操作性,SunJSSE默认情况下不为客户端连接启用TLS 1.1或TLS 1.2.

链接

要启用TLS 1.2,您可以使用VM的以下设置:-Dhttps.protocols=TLSv1.1,TLSv1.2然后它将起作用.

如果要查看有关握手的更多详细信息,可以使用此VM选项: -Djavax.net.debug=all

然后,如果您看到以下内容,则可以确认已禁用TLS 1.2:

*** ClientHello, TLSv1

读取服务器响应后,将抛出异常.Java 8没有这样的问题,因为默认情况下启用了TLS 1.2.

目前只有沙箱受到影响.您可以在PayPal的网站上阅读:

PayPal正在更新其服务,以便在2016年6月17日对所有HTTPS连接要求TLS v1.2.在该日期之后,将拒绝所有TLS v1.0和TLS v1.1 API连接.

最有可能的是,这将推迟更多.

您可以重现问题并尝试使用这个简单的丢弃代码:

URL sandbox = new URL("https://api.sandbox.paypal.com/v1/oauth2/token");
URLConnection yc = sandbox.openConnection();

BufferedReader in = new BufferedReader(new InputStreamReader(
    yc.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
   System.out.println(inputLine);
in.close();