Shr*_*Pai 6 javascript jquery json
我有这个示例JSON对象
var sample = [{
"label": "one",
"value": 1
}, {
"label": "two",
"value": 2
}, {
"label": "three",
"value": 3
}, {
"label": "four",
"value": 4
}, {
"label": "five",
"value": 5
}];
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我想改变这样的事情
var sample = [{
"label": "one",
"value": 1,
"newKeyValue": "one|1"
}, {
"label": "two",
"value": 2,
"newKeyValue": "two|2"
}, {
"label": "three",
"value": 3,
"newKeyValue": "three|3"
},
...
];
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它应该结合两个键值并返回组合两者的新键值.
JSON是动态的关键标签,价值不是静态的,它可以是任何东西.例如[{"name":"srinivas","lastname":"pai"}]
您可以像这样使用地图:
编辑
为了处理通用键,您可以将
Object.keys(d)[0]第一个键
Object.keys(d)[1]用于第二个键
var sample = [
{
"label":"one",
"value":1
},
{
"label":"two",
"value":2
},
{
"label":"three",
"value":3
},
{
"label":"four",
"value":4
},
{
"label":"five",
"value":5
}
];
var data = sample.map(function(d){
return {label: Object.keys(d)[0], value: Object.keys(d)[1], newKeyValue: Object.keys(d)[0] +"|" + Object.keys(d)[1]}
})
console.log(data)Run Code Online (Sandbox Code Playgroud)
希望这可以帮助!