用空格替换标点符号

Question

我的代码有问题,无法弄清楚如何前进.

tweet = "I am tired! I like fruit...and milk"
clean_words = tweet.translate(None, ",.;@#?!&$")
words = clean_words.split()

print tweet
print words

输出:

['I', 'am', 'tired', 'I', 'like', 'fruitand', 'milk']

我想要的是用空格替换标点符号但不知道使用什么函数或循环.有人可以帮我吗？

Answer 1

通过这样改变你的"maketrans"很容易实现:

import string
tweet = "I am tired! I like fruit...and milk"
translator = string.maketrans(string.punctuation, ' '*len(string.punctuation)) #map punctuation to space
print(tweet.translate(translator))

它适用于运行python 3.5.2的机器.希望它也适用于你的.

Answer 2

这是一个基于正则表达式的解决方案，已经在Python 3.5.1下进行了测试。我认为这既简单又简洁。

import re

tweet = "I am tired! I like fruit...and milk"
clean = re.sub(r"""
               [,.;@#?!&$]+  # Accept one or more copies of punctuation
               \ *           # plus zero or more copies of a space,
               """,
               " ",          # and replace it with a single space
               tweet, flags=re.VERBOSE)
print(tweet + "\n" + clean)

结果：

I am tired! I like fruit...and milk
I am tired I like fruit and milk

精简版：

tweet = "I am tired! I like fruit...and milk"
clean = re.sub(r"[,.;@#?!&$]+\ *", " ", tweet)
print(tweet + "\n" + clean)

Answer 3

有几种方法可以解决这个问题。我有一个有效的，但相信它是次优的。希望更了解正则表达式的人会出现并改进答案或提供更好的答案。

你的问题被标记为python-3.x，但你的代码是python 2.x，所以我的代码也是2.x。我包括一个适用于 3.x 的版本。

#!/usr/bin/env python

import re

tweet = "I am tired! I like fruit...and milk"
# print tweet

clean_words = tweet.translate(None, ",.;@#?!&$")  # Python 2
# clean_words = tweet.translate(",.;@#?!&$")  # Python 3
print(clean_words)  # Does not handle fruit...and

regex_sub = re.sub(r"[,.;@#?!&$]+", ' ', tweet)  # + means match one or more
print(regex_sub)  # extra space between tired and I

regex_sub = re.sub(r"\s+", ' ', regex_sub)  # Replaces any number of spaces with one space
print(regex_sub)  # looks good