让最后一个RecyclerView Item填充RecyclerView中的空格（如果数据计数为奇数）

Question

到目前为止我一直在尝试创建一个recyclerView，但现在我遇到了一个问题。

我需要让它看起来像这样

我需要将其设置为类似网格的列表，但是我无法将它们并排放置。

其次，如果最后一项是“单独的”，我需要最后一项来填充两个空格。

有任何想法吗？

Answer 1

我需要将其做成类似网格的列表

您可以使用RecyclerViewwith来实现它GridLayoutManager。例如，

// Initialize the view
recyclerView=(RecyclerView)findViewById(R.id.recyclerView);
// Here 2 is the number of columns
GridLayoutManager llm = new GridLayoutManager(this, 2);
recyclerView.setLayoutManager(llm);
recyclerView.setHasFixedSize(true);

如果最后一项是“单独的”，我需要最后一项来填充两个空格

要自定义网格项，我们可以使用ItemDecoration. 在您的情况下，最后一项（如果单独）应该具有父宽度。我们可以通过检查最后一项的位置来实现这一点。

现在，代码：

活动中

recyclerView=(RecyclerView)findViewById(R.id.recyclerView);
GridLayoutManager llm = new GridLayoutManager(this, 2);
recyclerView.setLayoutManager(llm);
recyclerView.setHasFixedSize(true);
recyclerView.addItemDecoration(new GridItemDecoration());
// And set adapter

GridItemDecoration.java

public class GridItemDecoration extends RecyclerView.ItemDecoration
{
    private int mHorizontalSpacing = 10;
    private int mVerticalSpacing = 10;

    @Override
    public void getItemOffsets(Rect outRect, View view, RecyclerView parent, RecyclerView.State state)
    {
        super.getItemOffsets(outRect, view, parent, state);
        // Only handle the vertical situation
        int position = parent.getChildPosition(view);
        if (parent.getLayoutManager() instanceof GridLayoutManager)
        {
            GridLayoutManager layoutManager = (GridLayoutManager) parent.getLayoutManager();
            int spanCount, column;
            // Check the last item and is alone. Then set the parent's width
            if (position == parent.getAdapter().getItemCount() - 1 && position % 2 == 0)
            {
                spanCount = 1;
                outRect.left = mHorizontalSpacing;
                outRect.right = parent.getWidth() - mHorizontalSpacing;
            }
            else
            {
                spanCount = layoutManager.getSpanCount();
                column = position % spanCount;
                outRect.left = mHorizontalSpacing * (spanCount - column) / spanCount;
                outRect.right = mHorizontalSpacing * (column + 1) / spanCount;
            }

            if (position < spanCount)
            {
                outRect.top = mVerticalSpacing;
            }
            outRect.bottom = mVerticalSpacing;
        }
    }
}