如何在sql server中间使用通配符,如查询

Question

在SQL Server中进行选择时,我可以在查询文本的开头或结尾添加%以表示我想要其他文本的任意数量的字符,但我不知道如何在中间执行此操作.

我想要SQL如下,

select *
From Table
Where name like '%[Error] Something failed in (%) session%'

这与下面的数据运行时

Row | Date      | Log Message
1   |2016-01-01 |'[Error] Something failed in (Freds) session'
2   |2016-01-01 |'[Error] Something failed in (Ilenes) session'
3   |2016-01-01 |'[Error] Something failed in (Freds) session'; Some other warning
4   |2016-01-01 |'[Warning] Something else went wrong'
5   |2016-01-01 |'[Warning] Some other warning'

会给我的

Row |Date       | Log Message
1   |2016-01-01 |'[Error] Something failed in (Freds) session'
2   |2016-01-01 |'[Error] Something failed in (Ilenes) session'
3   |2016-01-01 |'[Error] Something failed in (Freds) session'; Some other warning

但相反,它什么都没有回来,我需要改变什么.

Answer 1

问题是由于[]字符串的存在.[]与LIKE运算符一起使用来查找

指定范围内的任何单个字符([af])或set([abcdef]).

所以你需要ESCAPE在方括号的

select 1 
where '[Error] Something failed in (Freds) session'
like '%\[Error] Something failed in (%) session%' escape '\'

要么

select 1 
where '[Error] Something failed in (Freds) session'
like '%[[]Error] Something failed in (%) session%'

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