程序不搜索整个文件

Question

我正在写一个程序,我需要搜索几个完整的数字.搜索部分似乎有效但由于某种原因,该程序正在跳过几个单词.我的代码如下:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main(int argc, const char *argv[]){
    char temp[128];
    char *words[] = {"een","twee","drie","vier","vijf","zes","zeven","acht",
"negen","tien","elf","twaalf","dertien","veertien",
"vijftien","zestien","zeventien","achttien",
"negentien","twintig"};

    //Open the file
    FILE *myFile;
    myFile = fopen("numbers.txt","r");
    int count = sizeof(myFile);
    if (myFile == NULL){
        printf("File not found\n");
    }
    else {
        //Search the words
        while(!feof(myFile)){
            //Get the words
            fgets(temp, sizeof(temp), myFile);
                for (int i = 0; i < count; ++i){

                    if((strstr(temp, words[i])) != NULL) {
                    printf("%s\n", temp);
                    }

                }
        }
    }
    return 0;
}

提到的文件"numbers.txt"如下:

een
foo
drie
twee
acht
bla
zes
twaalf
elf
vier

节目输出:

een
drie
twee
acht
zes
vier

这意味着它正在跳过"twaalf"和"elf".为什么,我该如何解决这个问题？

感谢正手.

Answer 1

int count = sizeof(myFile);

这似乎是一个错字或误解.sizeof(myFile)计算指针使用的字节数.你需要使用:

int count = sizeof(words)/sizeof(words[0]);

值count将是之后的单词数.