efr*_*dze 17 enums switch-statement swift
我已经为Instagram端点创建了一个枚举,其嵌套枚举类似于Moya.
enum Instagram {
enum Media {
case Popular
case Shortcode(id: String)
case Search(lat: Float, lng: Float, distance: Int)
}
enum Users {
case User(id: String)
case Feed
case Recent(id: String)
}
}
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我想返回每个端点的路径.
extension Instagram: TargetType {
var path: String {
switch self {
case .Media.Shortcode(let id):
return "/media/shortcode"
}
}
}
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但是我在上面的switch语句中遇到错误path.
枚举案例
Shortcode不是类型的成员
怎么修?
Jef*_*eff 37
由于一些原因,我正在添加更一般的答案.
enum Action {
case fighter(F)
case weapon(W)
enum F {
case attack(A)
case defend(D)
case hurt(H)
enum A {
case fail
case success
}
enum D {
case fail
case success
}
enum H {
case none
case some
}
}
enum W {
case swing
case back
}
}
// Matches "3 deep"
let action = Action.fighter(.attack(.fail))
// Matches "1 deep" because more general case listed first.
let action2 = Action.weapon(.swing)
switch action {
case .fighter(.attack(.fail)):
print("3 deep")
case .weapon:
print("1 deep")
case .weapon(.swing):
print("2 deep to case")
case .fighter(.attack):
print("2 deep to another enum level")
default:
print("WTF enum")
}
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efr*_*dze 14
通过为嵌套枚举添加关联值,可以使用switch语句访问它.
enum Instagram {
enum MediaEndpoint {
case Search(lat: Float, lng: Float, distance: Int)
}
case Media(MediaEndpoint)
}
extension Instagram: TargetType {
var path: String {
switch self {
case .Media(.Search):
return "/media/search"
}
}
}
// Demo
protocol TargetType {
var path: String { get }
}
class MoyaProvider<Target: TargetType> {
func request(_ target: Target, completion: @escaping () -> ()) {}
}
let provider = MoyaProvider<Instagram>()
provider.request(.Media(.Search(lat: 0, lng: 0, distance: 0))) {}
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