Express和WebSocket在同一端口上侦听

Mor*_*nor 23 javascript websocket node.js

我有一个app.js,用于在收到一些POST数据时触发两个事件:

  1. 将POST数据插入数据库
  2. 使用WebSocket向客户端发送消息

这是app.js(只有重要的行)

var express = require('express');
var bodyParser = require('body-parser');
var server = require('./server');

var app = express();
var port = process.env.PORT || 3000;

app.post('/server', server);

app.listen(port, function(){
  console.log('Slack bot listening');
});
Run Code Online (Sandbox Code Playgroud)

这里是server.js(只有重要的行)

var db = require('./DB');
var WebSocketServer = require('ws').Server;

var insertData = function(req, res){

    var wss = new WebSocketServer({server: server});
    console.log('WebSocketServer created');
    wss.on('connection', function(wss){
        wss.send(JSON.stringify('Socket open'));
    });
    wss.on('close', function(){
        console.log('WebServerSocket has been closed');
    });
};

module.exports = insertData;
Run Code Online (Sandbox Code Playgroud)

我想要实现的是设置WebSocketServer以便它监听应用程序的同一端口.我想过将服务器 var从app.js传递给server.js但是

  1. 我认为这不是一种优雅的方式
  2. 我不知道怎么做

你们有什么感想?

Zla*_*tko 43

根据您的代码和注释,这是一个如何协同工作的超级简单示例.

首先,http-server.js- 一个典型的快递应用程序,除了我们不启动服务器app.listen():

'use strict';

let fs = require('fs');
let express = require('express');
let app = express();
let bodyParser = require('body-parser');

app.use(bodyParser.json());

// Let's create the regular HTTP request and response
app.get('/', function(req, res) {

  console.log('Get index');
  fs.createReadStream('./index.html')
  .pipe(res);
});

app.post('/', function(req, res) {

  let message = req.body.message;
  console.log('Regular POST message: ', message);
  return res.json({

    answer: 42
  });
});

module.exports = app;
Run Code Online (Sandbox Code Playgroud)

现在,ws-server.js我们从节点本机创建WSS服务器的示例http.createServer().现在,请注意,这是我们导入应用程序的位置,并为此本机http.createServer提供要使用的应用程序实例.

启动应用程序PORT=8080 node ws-server.js:

'use strict';

let WSServer = require('ws').Server;
let server = require('http').createServer();
let app = require('./http-server');

// Create web socket server on top of a regular http server
let wss = new WSServer({

  server: server
});

// Also mount the app here
server.on('request', app);

wss.on('connection', function connection(ws) {

  ws.on('message', function incoming(message) {

    console.log(`received: ${message}`);

    ws.send(JSON.stringify({

      answer: 42
    }));
  });
});


server.listen(process.env.PORT, function() {

  console.log(`http/ws server listening on ${process.env.PORT}`);
});
Run Code Online (Sandbox Code Playgroud)

最后,这个示例index.html将通过创建POST和Socket"请求"来工作并显示响应:

<html>
<head>
  <title>WS example</title>
</head>

<body>
  <h2>Socket message response: </h2>
  <pre id="response"></pre>
  <hr/>
  <h2>POST message response: </h2>
  <pre id="post-response"></pre>
  <script>

  // Extremely simplified here, no error handling or anything
document.body.onload = function() {

    'use strict';

  // First the socket requesta
  function socketExample() {
    console.log('Creating socket');
    let socket = new WebSocket('ws://localhost:8080/');
    socket.onopen = function() {

      console.log('Socket open.');
      socket.send(JSON.stringify({message: 'What is the meaning of life, the universe and everything?'}));
      console.log('Message sent.')
    };
    socket.onmessage = function(message) {

      console.log('Socket server message', message);
      let data = JSON.parse(message.data);
      document.getElementById('response').innerHTML = JSON.stringify(data, null, 2);
    };
  }

  // Now the simple POST demo
  function postExample() {

    console.log('Creating regular POST message');

    fetch('/', {  
      method: 'post',  
      headers: {  
        "Content-type": "application/json"  
      },  
      body: JSON.stringify({message: 'What is the meaning of post-life, the universe and everything?'})  
    })
    .then(response => response.json())  
    .then(function (data) {  

      console.log('POST response:', data);
      document.getElementById('post-response').innerHTML = JSON.stringify(data, null, 2);   
    })  
    .catch(function (error) {  
      console.log('Request failed', error);  
    });   
  }

  // Call them both;

  socketExample();
  postExample();
}
  </script>
</body>
</html>
Run Code Online (Sandbox Code Playgroud)

请注意,您需要一个非常新的浏览器,一个同时具有WebSocket和fetch API的客户端部分,但无论如何它都无关紧要,它只是为您提供了它的要点.

  • Waow @Zlatko,这是一个地狱的答案.非常感谢你为我服用的时间.非常感激!完美的工作. (6认同)

Fat*_*tie 6

http 和 ws 在同一端口 80 上,“Amazing Zlatko Method™”。

你会有一个文件,比如 main.js,

 var app = express()
Run Code Online (Sandbox Code Playgroud)

以及多行快速代码。

以通常的方式拥有您想要的尽可能多的中间件而无需任何更改是完全可以的。

var app = express()
app.use(session(session_options))
app.use(passport.initialize())
app.use(passport.session())
app.use('/static', express.static('static'))
// etc etc
app.get ...
app.get ...
app.post ...
app.post ...
Run Code Online (Sandbox Code Playgroud)

通常在该文件末尾,您会

 app.listen(80, (err) => { ... })
Run Code Online (Sandbox Code Playgroud)

删除那个。

 //app.listen(80, (err) => { ... })
Run Code Online (Sandbox Code Playgroud)

express 应用程序文件中没有其他更改

在你的 websocket 文件中,比如 multiplayer.js,你通常会有

const WebSocket = require('ws');
const wss = new WebSocket.Server({
    port: 9999,
    perMessageDeflate: false
})
Run Code Online (Sandbox Code Playgroud)

事实上,改为

const WebSocket = require('ws');
/*const wss = new WebSocket.Server({
    port: 2828,
    perMessageDeflate: false
});*/
let WSServer = WebSocket.Server;
let server = require('http').createServer();
let app = require('./main'); // note, that's your main.js file above
let wss = new WSServer({
  server: server,
  perMessageDeflate: false
})
server.on('request', app);
Run Code Online (Sandbox Code Playgroud)

在那个文件的末尾

server.listen(80, function() {
    console.log(`Amazing Zlatko Method™ combo server on 80`);
});
Run Code Online (Sandbox Code Playgroud)

笔记!- 启动“multiplayer.js”文件(不是“main.js”)。

它完美地工作。惊人的东西。