Moh*_*ahu 5 javascript mysql triggers node.js
我有一个后插入触发器.调用存储过程.当我运行直接查询时,它运行良好.但是当我通过节点js app插入数据时.它甚至不在主表中插入数据.触发器和存储过程中没有任何错误,因为它适用于表的直接插入查询.
dbObject.create(data, function(err, response){
if (err) {
//console.log("err", err);
res.status(500).jsonp(response)
}
console.log("response", response);
dbObject.find({SnsId: SnsId}, '*' , {}, 0, 0, {}, function(err, resp){
if (err) {
//console.log("err", err);
res.status(500).jsonp(err)
}
console.log("response", resp);
res.jsonp(resp);
});
});
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触发代码 -
DELIMITER $$
CREATE TRIGGER `copytoSensorMapTrigger` AFTER INSERT ON test4.`SENSORS`
FOR EACH ROW
BEGIN
CALL copyToSensorMap(NEW.`SnsId`,NEW.`SnsState`);
END;
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存储过程代码 -
DELIMITER $$
CREATE PROCEDURE copyToSensorMap(IN snsid bigint(20),IN sns_state varchar(128))
BEGIN
DECLARE color varchar(128);
INSERT INTO test3.`SENSOR_MAP` (`SENSOR_ID`, `SENSOR_NAME`, `USER_ID`, `HOST_ID`, `SENSOR_STATE`)
SELECT `SnsId`,
`SnsName`,`SnsOwner`,`HostId`,`SnsState`
FROM test4.`SENSORS`
where test4.`SENSORS`.`SnsId`=snsid;
IF ( sns_state ='Unassigned') THEN
set color = 'Grey';
ELSEIF ( sns_state ='Running') THEN
set color = 'Green';
END IF;
update test3.`SENSOR_MAP`
set test3.`SENSOR_MAP`.`SENSOR_COLOR` = color
where test3.`SENSOR_MAP`.`SENSOR_ID` = snsid;
UPDATE test3.`SENSOR_MAP`
INNER JOIN test4.`HOSTS`
ON (test3.`SENSOR_MAP`.`HOST_ID` = test4.`HOSTS`.id)
SET
test3.`SENSOR_MAP`.HOST_NAME = test4.HOSTS.Name,
test3.`SENSOR_MAP`.LATITUDE = test4.HOSTS.GpsLatitude,
test3.`SENSOR_MAP`.LONGITUDE = test4.HOSTS.GpsLongitude;
UPDATE test3.`SENSOR_MAP`
INNER JOIN test4.`users` ON (test3.`SENSOR_MAP`.`USER_ID` = test4.`users`.id)
SET
test3.`SENSOR_MAP`.USER_NAME = test4.users.user;
UPDATE test3.`SENSOR_MAP` c
INNER JOIN
(
select a.`SnsId`,b.id,b.ServiceName,b.ServiceType
from test4.sensors as a
join test4.SESSIONS as b on a.SessionId =b.id
where a.`SnsId` =snsid
group by `SnsId`
) d ON c.SENSOR_ID = d.`SnsId`
SET c.SESSION_NAME = d.ServiceName,
c.SESSION_TYPE = d.ServiceType;
END $$
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我使用的是Mysql数据库,存储引擎是InnoDB.我检查了sql查询.它是用SET Keyword形成的.在插入存储过程之后,Mysql是否使用set关键字支持插入查询.
问题现在解决了.它是Mysql中所有大写的表名,我用lowercase.tables命名为"user"和"sensor".现在它解决了.
小智 1
return我还建议在检查错误的地方使用,否则代码将继续,并且在出现错误时不会停止。
尝试使用此代码:
dbObject.create(data, function(err, response){
if (err) {
//console.log("err", err);
return res.status(500).jsonp(response)
}
console.log("response", response);
dbObject.find({SnsId: SnsId}, '*' , {}, 0, 0, {}, function(err, resp){
if (err) {
//console.log("err", err);
return res.status(500).jsonp(err)
}
console.log("response", resp);
res.jsonp(resp);
});
});
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