了解实现自定义迭代器

Bar*_*ski 4 javascript ecmascript-6

我试图理解Ecmascript 6迭代器并尝试创建一个与本机阵列非常相似的数据结构.

for (let i of [1,2,3]) console.log(i);  //Iterate over data set itself
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将输出 1,2,3

for (let i of [1,2,3].keys()) console.log(i); //Iterate over a custom iterator from a method
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将输出0,1,2,和

var a = [1,2,3];
var keys = [...a.keys()];
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将按[0,1,2]预期包含.

因此,

console.log([1,2,3].keys().next());
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将输出 Object {value: 0, done: false}

现在我创建了一种新类型的数据,并尝试使其行为方式相同.

var myDogs = function(dogs) {
 this.dogs = dogs;
 this[Symbol.iterator] = () => {
   let i = -1;
   return {
    next() {
     i++;
     var dog = Object.keys(dogs)[i];
     if (!dog) return {done:true};
     return {value:{ dog, hungry:dogs[dog] }, done:false};
    }
   };
 };
 this.dogsNames = () => {
  return {
   [Symbol.iterator]() {
     let i = -1;
     return {
      next() {
       i++;
       var dog = Object.keys(dogs)[i];
       if (!dog) return {done:true};
       return {value: dog, done:false};
      }
     };
   }
  }
 }
};

var dogs = new myDogs({ buddy: true, hasso: false });
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这按预期工作(自定义迭代器 - 谢谢):

var dogHungryMap = [...dogs];
dogHungryMap == [{ dog: 'buddy', hungry: true }, { dog: 'hasso': hungry: false }]
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迭代器dogsNames()的工作原理几乎如预期.还行吧:

var names = [...dogs.dogsNames()];
names == ["buddy", "hasso"]
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但这不是:

dogs.dogsNames().next()
VM19728:2 Uncaught TypeError: dogs.dogsNames(...).next is not a function(…)
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为什么以及如何重现本机数组的行为?

Cod*_*gue 5

因为dogsNames()返回一个具有迭代器作为键的对象.所以你可以使用for...ofdogNames,但要next()直接访问你需要访问在对象上声明的迭代器函数,如下所示:

dogsNames()[Symbol.iterator]().next()
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Babel REPL示例

为了完整性,共享next()函数的完整代码:

var myDogs = function(dogs) {
 this.dogs = dogs;
 let i = -1;
 var iter = {
   next() {
     i++;
     var dog = Object.keys(dogs)[i];
     if (!dog) return {done:true};
     return {value:{ dog, hungry:dogs[dog] }, done:false};
   }
 }
 this[Symbol.iterator] = () => iter;
 this.next = iter.next;
};
var dogList = new myDogs({
  dog1: "no",
  dog2: "yes"
});
for(const x of dogList) console.log(x);
console.log(dogList.next());
console.log(dogList.next());
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