使用BeautifulSoup从span类中提取锚文本

Question

这是我试图抓取的HTML:

<span class="meta-attributes__attr-tags">
<a href="/tags/cinematic" title="cinematic">cinematic</a>, 
<a href="/tags/dissolve" title="dissolve">dissolve</a>,
<a href="/tags/epic" title="epic">epic</a>,
<a href="/tags/fly" title="fly">fly</a>,
</span>

我想得到每个href的锚文本:电影,溶解,史诗等.

这是我的代码:

url = urllib2.urlopen("http: example.com")

content = url.read()
soup = BeautifulSoup(content)

links = soup.find_all("span", {"class": "meta-attributes__attr-tags"})
for link in links:
    print link.find_all('a')['href']

如果我用"link.find_all"来做,我得到错误:TypeError:List索引必须是整数,而不是str.

但是,如果我打印link.find('a')['href']我只得到第一个.

我怎样才能得到所有这些？

Answer 1

您可以执行以下操作:

from bs4 import BeautifulSoup

content = '''
<span class="meta-attributes__attr-tags">
<a href="/tags/cinematic" title="cinematic">cinematic</a>, 
<a href="/tags/dissolve" title="dissolve">dissolve</a>,
<a href="/tags/epic" title="epic">epic</a>,
<a href="/tags/fly" title="fly">fly</a>,
</span>
'''

soup = BeautifulSoup(content)
spans = soup.find_all("span", {"class": "meta-attributes__attr-tags"})
for span in spans:
    links = span.find_all('a')
    for link in links:
        print link['href']

产量

/tags/cinematic
/tags/dissolve
/tags/epic
/tags/fly