use*_*252 5 sql postgresql count where having
亲爱的朋友Stackoverflowers,
如何从场景中的同一个表中选择2个不同的计数:
x=a and x=b
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具体来说,(WHEN type = subdomain)AND(WHEN subtype = subdomain)?
将它们添加到一起以创建'totalcount'?
我的尝试(供你参考):
SELECT description, type, count(1), subtype, count(2)
FROM mapping, (dotcom WHERE type = subdomain) AS typecount,
(dotcom WHERE subtype = subdomain) AS subtypecount
GROUP BY description, type, subtype
HAVING count(1)>1
AND count(2)>1
ORDER BY count(*)
DESC LIMIT 10
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第二次尝试:
SELECT description
FROM mapping, SUM(WHEN subdomain = type OR subdomain = subtype) AS count(1)
GROUP BY description, type, subtype
HAVING count(1)>1
ORDER BY count(*)
DESC LIMIT 10
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如果我正确理解你的要求,你可以这样做
SELECT description, SUM(CASE WHEN subdomain = type OR subdomain = subtype THEN 1 ELSE 0 END)
FROM mapping
GROUP BY description
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