直接从文件系统以标准RFC邮件格式使用Java读取/解析电子邮件/邮件

Sim*_*n B 3 java email parsing

我想使用Java(1.6)直接从文件系统解析电子邮件,电子邮件将位于文件系统文件夹中,例如

abc-12345.msg qwe-23456.msg

并将采用标准格式:例如:

MIME-Version: 1.0
Sender: mr.sender@gmail.com
Received: by 10.239.173.80 with HTTP; Thu, 12 Aug 2010 11:30:50 -0700 (PDT)
Date: Thu, 12 Aug 2010 15:30:50 -0300
Delivered-To: mr.recipient@gmail.com
Message-ID: <AANLkTikA-RbE_revkimBCWC2fUrG=t4T47AXq5FTx0vd@mail.gmail.com>
Subject: =?ISO-8859-1?Q?Hello_With_Acc=E9=F1ts?=
From: Mr Sender <mr.sender@gmail.com>
To: Mr Recipient <mr.recipient@gmail.com>
Content-Type: text/plain; charset=ISO-8859-1
Content-Transfer-Encoding: quoted-printable

This is a testing one

Accent characters:

=E9=F3=FA=F1

Email End
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我想解析此文件或使用现有的库来解析该文件,以使我可以访问标题/ from / to / subject / body等。

文件全部保存在本地文件系统上。我无法通过pop / imap连接到消息存储。对我而言,最简单,最直接的方法是什么。这些文件可能包含附件。

任何建议都非常欢迎。如果现有的api(也许是javamail)可以做到这一点,请提供示例或示例参考。

干杯西蒙

Sim*_*n B 5

使用javamail api:

例如:

  File[] mailFiles = getPertinentMailFiles();
  String host = "host.com";
  java.util.Properties properties = System.getProperties();
  properties.setProperty("mail.smtp.host", host);
  Session session = Session.getDefaultInstance(properties);
  for (File tmpFile : mailFiles) {
     MimeMessage email = null;
     try {
        FileInputStream fis = new FileInputStream(tmpFile);
        email = new MimeMessage(session, fis);
        System.out.println("content type: " + email.getContentType());
        System.out.println("\nsubject: " + email.getSubject());
        System.out.println("\nrecipients: " + Arrays.asList(email.getRecipients(Message.RecipientType.TO))); 
     } catch (MessagingException e) {
        throw new IllegalStateException("illegal state issue", e);
     } catch (FileNotFoundException e) {
        throw new IllegalStateException("file not found issue issue: " + tmpFile.getAbsolutePath() , e); 
     }
  }
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