moo*_*avi 11 android json httprequest wp-api
我想使用wp-api插件为我的wordpress网站构建一个Android应用程序.我如何在Json中发送HttpRequest(GET)和recive响应?
Asa*_*der 29
使用此函数从URL获取JSON.
public static JSONObject getJSONObjectFromURL(String urlString) throws IOException, JSONException {
HttpURLConnection urlConnection = null;
URL url = new URL(urlString);
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestMethod("GET");
urlConnection.setReadTimeout(10000 /* milliseconds */ );
urlConnection.setConnectTimeout(15000 /* milliseconds */ );
urlConnection.setDoOutput(true);
urlConnection.connect();
BufferedReader br = new BufferedReader(new InputStreamReader(url.openStream()));
StringBuilder sb = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
String jsonString = sb.toString();
System.out.println("JSON: " + jsonString);
return new JSONObject(jsonString);
}
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不要忘记在清单中添加Internet权限
<uses-permission android:name="android.permission.INTERNET" />
然后像这样使用它:
try{
JSONObject jsonObject = getJSONObjectFromURL(urlString);
//
// Parse your json here
//
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
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Ija*_*d N 13
尝试以下代码从URL获取json
HttpClient httpclient = new DefaultHttpClient();
HttpGet httpget= new HttpGet(URL);
HttpResponse response = httpclient.execute(httpget);
if(response.getStatusLine().getStatusCode()==200){
String server_response = EntityUtils.toString(response.getEntity());
Log.i("Server response", server_response );
} else {
Log.i("Server response", "Failed to get server response" );
}
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