如何检测对话框的关闭事件？

Question

嗨,大家好.

我正在使用Windows 7中的python3.4,PyQt5制作GUI应用程序.

申请很有样.用户单击主窗口的按钮,弹出信息对话框.当用户单击信息对话框的关闭按钮(窗口的X按钮)时,系统会显示确认消息.这是所有的了.

这是我的代码.

# coding: utf-8

import sys
from PyQt5.QtWidgets import QApplication, QMainWindow, QPushButton, QDialog, QLabel

class mainClass(QMainWindow):
    def __init__(self):
        super().__init__()
        self.initUI()

    def initUI(self):
        openDlgBtn = QPushButton("openDlg", self)
        openDlgBtn.clicked.connect(self.openChildDialog)
        openDlgBtn.move(50, 50)

        self.setGeometry(100, 100, 200, 200)
        self.show()

    def openChildDialog(self):
        childDlg = QDialog(self)
        childDlgLabel = QLabel("Child dialog", childDlg)

        childDlg.resize(100, 100)
        childDlg.show()


if __name__ == "__main__":
    app = QApplication(sys.argv)
    mc = mainClass()
    sys.exit(app.exec_())

结果截图是......

在这种情况下,我在mainClass类中添加了这些代码.

def closeEvent(self, event):
    print("X is clicked")

此代码仅在主窗口关闭时有效.但是我想要的是closeEvent函数在关闭childDlg时有效.不是主窗口.

我该怎么办？

Answer 1

你已经添加了类mainClass中的方法closeEvent.所以你已经重新实现了QMainwindow的方法closeEvent而不是你的childDlg的closeEvent方法.要做到这一点,你必须像这样继承你的chilDlg:

# coding: utf-8

import sys
from PyQt5.QtWidgets import QApplication, QMainWindow, QPushButton, QDialog, QLabel

class ChildDlg(QDialog):
   def closeEvent(self, event):
      print("X is clicked")

class mainClass(QMainWindow):
    def __init__(self):
        super().__init__()
        self.initUI()

    def initUI(self):
        openDlgBtn = QPushButton("openDlg", self)
        openDlgBtn.clicked.connect(self.openChildDialog)
        openDlgBtn.move(50, 50)

        self.setGeometry(100, 100, 200, 200)
        self.show()

    def openChildDialog(self):
        childDlg = ChildDlg(self)
        childDlgLabel = QLabel("Child dialog", childDlg)

        childDlg.resize(100, 100)
        childDlg.show()


if __name__ == "__main__":
    app = QApplication(sys.argv)
    mc = mainClass()
    sys.exit(app.exec_())