BKa*_*Kay 5 python numpy time-series pandas
我使用以下 Python 代码生成混合类型(浮点数和字符串)Pandas DataFrame df3:
df1 = pd.DataFrame(np.random.randn(dates.shape[0],2),index=dates,columns=list('AB'))
df1['C'] = 'A'
df1['D'] = 'Pickles'
df2 = pd.DataFrame(np.random.randn(dates.shape[0], 2),index=dates,columns=list('AB'))
df2['C'] = 'B'
df2['D'] = 'Ham'
df3 = pd.concat([df1, df2], axis=0)
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当我将 df3 重新采样到更高的频率时,我不会将帧重新采样到更高的速率,但是如何忽略,我只会得到缺失值:
df4 = df3.groupby(['C']).resample('M', how={'A': 'mean', 'B': 'mean', 'D': 'ffill'})
df4.head()
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结果:
B A D
C
A 2014-03-31 -0.4640906 -0.2435414 Pickles
2014-04-30 NaN NaN NaN
2014-05-31 NaN NaN NaN
2014-06-30 -0.5626360 0.6679614 Pickles
2014-07-31 NaN NaN NaN
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当我将 df3 重新采样到较低频率时,我根本没有得到任何重新采样:
df5 = df3.groupby(['C']).resample('A', how={'A': np.mean, 'B': np.mean, 'D': 'ffill'})
df5.head()
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结果:
B A D
C
A 2014-03-31 NaN NaN Pickles
2014-06-30 NaN NaN Pickles
2014-09-30 NaN NaN Pickles
2014-12-31 -0.7429617 -0.1065645 Pickles
2015-03-31 NaN NaN Pickles
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我很确定这与混合类型有关,因为如果我只用数字列重做年度下采样,一切都会按预期工作:
df5b = df3[['A', 'B', 'C']].groupby(['C']).resample('A', how={'A': np.mean, 'B': np.mean})
df5b.head()
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结果:
B A
C
A 2014-12-31 -0.7429617 -0.1065645
2015-12-31 -0.6245030 -0.3101057
B 2014-12-31 0.4213621 -0.0708263
2015-12-31 -0.0607028 0.0110456
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但即使我切换到数字类型,重新采样到更高的频率仍然不能像我预期的那样工作:
df4b = df3[['A', 'B', 'C']].groupby(['C']).resample('M', how={'A': 'mean', 'B': 'mean'})
df4b.head()
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结果:
B A
C
A 2014-03-31 -0.4640906 -0.2435414
2014-04-30 NaN NaN
2014-05-31 NaN NaN
2014-06-30 -0.5626360 0.6679614
2014-07-31 NaN NaN
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这让我有两个问题:
即使您不能对这两部分都提供完整的答案,也欢迎部分解决方案或任一问题的答案。
当从较低频率重新采样到较高频率时,我意识到我在指定fill_method时指定了方式。当我这样做时,一切似乎都有效。
df4c = df3.groupby(['C']).resample('M', fill_method='ffill')
df4c.head()
A B D
C
A 2014-03-31 -0.2435414 -0.4640906 Pickles
2014-04-30 -0.2435414 -0.4640906 Pickles
2014-05-31 -0.2435414 -0.4640906 Pickles
2014-06-30 0.6679614 -0.5626360 Pickles
2014-07-31 0.6679614 -0.5626360 Pickles
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您可以获得一组更加有限的插值选择,但它确实可以处理混合类型。
当使用 no how选项(我相信它默认为mean)重新采样到较低频率时,下采样确实有效:
df5c =df3.groupby(['C']).resample('A')
df5c.head()
A B
C
A 2014-12-31 -0.1065645 -0.7429617
2015-12-31 -0.3101057 -0.6245030
B 2014-12-31 -0.0708263 0.4213621
2015-12-31 0.0110456 -0.0607028
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因此,问题似乎在于传递如何选项或选项之一的字典,大概是ffill,但我不确定。
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