将RDD中的元组分解为两个元组

Question

我有一个RDD[(String, (Iterable[Int], Iterable[Coordinate]))] 我想做的,是打破Iterable[Int]元组,每个人都会喜欢(String,Int,Iterable[Coordinate])

举个例子,我想改造:

('a',<1,2,3>,<(45.34,32.33),(45.36,32.34)>)
('b',<1>,<(46.64,32.66),(46.67,32.71)>)

至

('a',1,<(45.34,32.33),(45.36,32.34)>)
('a',2,<(45.34,32.33),(45.36,32.34)>)
('a',3,<(45.34,32.33),(45.36,32.34)>)
('b',1,<(46.64,32.66),(46.67,32.71)>)

Scala是怎么做的？

Answer 1

尝试使用flatMap:

rdd.flatMap {case (v, i1, i2) => i1.map(i=>(v, i, i2)}