Chr*_*ice 1 activerecord ruby-on-rails database-migration
我User和Course(典型的注册数据)之间有关系.A User has_many Course,反之亦然(典型JOIN表格方案).
我试图has_and_belongs_to_many将这两个模型之间的关系迁移到has_many :through关系中.我的文件目前看起来像:
class User < ActiveRecord::Base
has_and_belongs_to_many :courses
end
Run Code Online (Sandbox Code Playgroud)
和
class Course < ActiveRecord::Base
has_and_belongs_to_many :users
end
Run Code Online (Sandbox Code Playgroud)
和连接两个模型的表名是courses_users.
我现在需要将此关系迁移到has_many :through关联,并且还要使列类型为user_ida string,因为我想使用g_number(字符串)属性User作为外键.注意:我不关心int和之间的性能差异varchar/string.
简短的问题是我需要users.g_number引用enrollments.user_id外键,两者都是字符串.
我尝试迁移和模型返工是这样的:
class User < ActiveRecord::Base
has_many :enrollment
has_many :courses, :through => :enrollment
end
Run Code Online (Sandbox Code Playgroud)
和
class Course < ActiveRecord::Base
has_many :enrollment
has_many :users, :through => :enrollment
end
Run Code Online (Sandbox Code Playgroud)
最后
class Enrollment < ActiveRecord::Base
belongs_to :course
belongs_to :user
end
Run Code Online (Sandbox Code Playgroud)
那么迁移
class ChangeUserIdJoin < ActiveRecord::Migration
def self.up
rename_table :courses_users, :enrollments
end
def self.down
rename_table :enrollments, :courses_users
end
end
Run Code Online (Sandbox Code Playgroud)
这里一切都很好.我可以做User.courses和的查询Course.users.但是现在我想user_id将连接表中列的类型更改为a,string以便我可以存储g_number(字符串属性User)并连接到该字符串而不是串行id列User.
当我尝试将user_id列类型更改string为迁移时:
class ChangeUserIdJoin < ActiveRecord::Migration
def self.up
change_column :courses_users, :user_id, :string
rename_table :courses_users, :enrollments
end
def self.down
rename_table :enrollments, :courses_users
change_column :courses_users, :user_id, :integer
end
end
Run Code Online (Sandbox Code Playgroud)
查询Course.users并User.courses开始失败(下面是Rails控制台).User.courses返回一个空数组(而在有多个Course对象之前),并Course.users因为列类型不匹配而引发异常(这显然是有意义的):
u = User.take
User Load (0.9ms) SELECT "users".* FROM "users" LIMIT 1
=> #<User id: 1, username: "director", g_number: "g00000000", password_digest: "$2a$10$dvcOd3rHfbcR1Rn/D6VhsOokj4XiIkQbHxXLYjy5s4f...", created_at: "2016-01-06 01:36:00", updated_at: "2016-01-06 01:36:00", first_name: "Director", last_name: "", role: 0, registered: true>
2.1.5 :002 > u.courses
Course Load (0.9ms) SELECT "courses".* FROM "courses" INNER JOIN "enrollments ON "courses"."id" = "enrollments"."course_id" WHERE "enrollments"."user_id" = $1 [["user_id", 1]]
=> #<ActiveRecord::Associations::CollectionProxy []>
2.1.5 :003 > c = Course.take
Course Load (0.7ms) SELECT "courses".* FROM "courses" LIMIT 1
=> #<Course id: 12754, year: 2015, semester: 0, department: 7, course: 101, section: 1, name: "SPA 101 01 - Elementary Spanish I">
2.1.5 :004 > c.users
PG::UndefinedFunction: ERROR: operator does not exist: integer = character varying
LINE 1: ... "users" INNER JOIN "enrollments" ON "users"."id" = "enrollm...
Run Code Online (Sandbox Code Playgroud)
我需要能够加入enrollments.user_id = users.g_number.我需要做什么才能将user_id列更改为模型/表中的string类型Enrollment,并且仍然可以执行User.courses和Course.users?之类的Active Record查询?
尝试在注册模型中指定外键和主键,如下所示
belongs_to :user foreign_key: :user_id, primary_key: :g_number
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
2132 次 |
| 最近记录: |