How do I select the next "n" elements starting from the current element in jQuery?

Question

How do I select the next "n" elements starting from the current element? What I mean is...

 $(this).attr(...);

I want to do this "n" times. For the example of n=4:

$(this).attr(...);
$(this).next().attr(...);
$(this).next().next().attr(...);
$(this).next().next().next().attr(...);

or perhaps do it in a loop:

for (i = 0; i < n; i++) {
    $(this).next().attr(...);
}

How can I do this? Is there a way I can do this by selecting the next "n" elements or in a loop?

Answer 1

这应该工作:

$(this).nextAll().slice(0,4).attr(…)

更新:

这也有效:

$(this).nextAll("*:lt(4)").attr(…)

Answer 2

该nextAll方法选择元素的以下兄弟节点,可选地由选择器过滤.然后,您可以使用a slice来限制更小的n.