在laravel测试中调用命名路由

The*_*ebs 6 testing phpunit unit-testing laravel-5 laravel-5.2

考虑以下:

<?php

use Illuminate\Foundation\Testing\WithoutMiddleware;
use Illuminate\Foundation\Testing\DatabaseMigrations;
use Illuminate\Foundation\Testing\DatabaseTransactions;

class HomeRouteTest extends TestCase
{
    public function testVisitTheHomePage()
    {
        $response = $this->call('GET', '/');
        $this->assertEquals(200, $response->status());

    }

    public function testVisitTheAboutPage()
    {
        $response = $this->call('GET', '/about');
        $this->assertEquals(200, $response->status());
    }
}
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离开了,而不是我见过记录>.>,做类似的事情:

$response = $this->call('GET', 'home.about');
$this->assertEquals(200, $response->status());
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或者....你是怎么做到的?

我得到的错误是:

vagrant@scotchbox:/var/www$ phpunit
PHPUnit 4.8.21 by Sebastian Bergmann and contributors.

FF

Time: 3.41 seconds, Memory: 14.25Mb

There were 2 failures:

1) HomeRouteTest::testVisitTheHomePage
Failed asserting that 404 matches expected 200.

/var/www/tests/HomeRouteTest.php:12

2) HomeRouteTest::testVisitTheAboutPage
Failed asserting that 404 matches expected 200.

/var/www/tests/HomeRouteTest.php:19

FAILURES!
Tests: 2, Assertions: 2, Failures: 2.
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小智 7

据我所知,此解决方案适用于任何 Laravel 5 版本。尤其是 Laravel 5.4+ 与这里提到的其他解决方案不同。

如果你的命名路由有参数,你可以这样做:

$response = $this->get(route('users.show', [
    'user' => 3,
]));

$response->assertStatus(200);
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如果您的命名路由没有参数,那么您可以这样做:

$response = $this->get(route('users.index'));

$response->assertStatus(200);
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好看又简单。


小智 5

这是一个很晚的回复,但我认为您正在寻找的是:

$this->route('GET', 'home.about');
$this->assertResponseOk(); // Checks that response status was 200
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对于带参数的路由,可以这样做:

$this->route('GET', 'users.show', ['id' => 3]); // (goes to '/users/3')
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我需要这个来测试我正在使用的一些可怕的路线,如下所示:

Route::resource(
    '/accounts/{account_id}/users',
    'AccountsController@users',
    [
        'parameters' => ['account_id'],
        'names'      => [
            'create'  => 'users.create',
            'destroy' => 'users.destroy',
            'edit'    => 'users.edit',
            'show '   => 'users.show',
            'store'   => 'users.store',
            'update'  => 'users.update',
        ]
    ]
);
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为了确保我的路线和重定向到达正确的页面,我这样做了:

/**
 * @test
 */
public function users_index_route_loads_correct_page()
{
    $account = Account::first();

    $response = $this->route('get', 'users.index', ['account_id' => $account->id]);
    $this->assertResponseOk()
        ->seePageIs('/accounts/' . $account->id . '/users');
}
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为了确保我使用正确的视图文件(我们都会犯复制粘贴错误,对吧?),我这样做了:

/**
 * @test
 */
public function users_index_route_uses_expected_view()
{
    $account = Account::first();

    $response = $this->route('get', 'users.index', ['account_id' => $account->id]);

    $view = $response->original; // returns View instance
    $view_name = $view->getName();

    $this->assertEquals($view_name, 'users.index'); 
}
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如果不是 PHPStorm 中的 Structure 功能和我偶然发现的 Laravel 4.2 文档,我想我永远不会弄清楚如何测试这些路由。我希望这可以节省其他人一些时间。

  • 这在 Laravel 5.4 中不再有效 - 调用未定义的方法route() (10认同)