所有可能的结果,需要循环

Question

我列出了所有英超球队的名单:

teamlist = ["arsenal", "aston-villa", "bournemouth", "chelsea", "crystal-palace", "everton","leicester-city", "liverpool", "manchester-city", "manchester-united", "newcastle-united", "norwich-city", "southampton","stoke-city", "swansea-city", "tottenham-hotspur", "watford", "west-bromich-albion","west-ham-united" ]

我需要计算所有可能的team1-vs-team2配对.

目前我有以下代码:

oppo = 0

for team in teamlist:
        print team + "-vs-" + teamlist[oppo]
        oppo+=1
        print team + "-vs-" + teamlist[oppo]
        oppo+=1

这将输出:

arsenal-vs-arsenal
arsenal-vs-aston-villa

然而,我需要通过每个团队,显示他们所有可能的主场比赛装置,然后进入团队列表中的下一个团队,输出他们所有可能的主场比赛装置并重复直到所有球队完成.

Answer 1

嵌套for循环的替代方法是从列表的项目计算长度为2的所有排列.

>>> from itertools import permutations
>>> for team1, team2 in permutations(teamlist, 2):
...     print '{0} -vs- {1}'.format(team1, team2)
... 
arsenal -vs- aston-villa
arsenal -vs- bournemouth
arsenal -vs- chelsea
# and so on ...