ListView与三角形项目

Question

我需要实现一个带有三角形项目的ListView,如图所示.添加到ListView的视图通常是矩形的.即使在文档中,视图也被描述为"占据屏幕上的矩形区域并负责绘图和事件处理".

如何将非矩形形状添加到ListView,同时确保单击区域仅限于形状,在本例中为三角形.

谢谢!

Answer 1

我的解决方案将使用重叠视图,这些视图被裁剪为交替三角形,并且仅接受其三角形内的触摸事件.

问题是ListView并不真正支持重叠的项目视图,因此我的示例只是将所有项目一次加载到ScrollView中,如果您有超过30个项目,这可能会很糟糕.也许这对RecyclerView来说是可行的,但我还没有考虑过.

我已选择扩展FrameLayout以实现三角形View逻辑,因此您可以将其用作列表项的根视图并将所需内容放入其中:

public class TriangleFrameLayout extends FrameLayout {

    // TODO: constructors

    public enum Align { LEFT, RIGHT };

    private Align alignment = Align.LEFT;

    /**
     * Specify whether it's a left or a right triangle.
     */
    public void setTriangleAlignment(Align alignment) {
        this.alignment = alignment;
    }

    @Override
    public void draw(Canvas canvas) {
        // crop drawing to the triangle shape
        Path mask = new Path();
        Point[] tria = getTriangle();
        mask.moveTo(tria[0].x, tria[0].y);
        mask.lineTo(tria[1].x, tria[1].y);
        mask.lineTo(tria[2].x, tria[2].y);
        mask.close();

        canvas.save();

        canvas.clipPath(mask);
        super.draw(canvas);

        canvas.restore();
    }

    @Override
    public boolean onTouchEvent(MotionEvent event) {
        // check if touch event is within the triangle shape
        if (event.getActionMasked() == MotionEvent.ACTION_DOWN) {
            Point touch = new Point((int) event.getX(), (int) event.getY());
            Point[] tria = getTriangle();

            if (!isPointInsideTrigon(touch, tria[0], tria[1], tria[2])) {
                // ignore touch event outside triangle
                return false;
            }
        }

        return super.onTouchEvent(event);
    }

    private boolean isPointInsideTrigon(Point s, Point a, Point b, Point c) {
        // stolen from http://stackoverflow.com/a/9755252
        int as_x = s.x - a.x;
        int as_y = s.y - a.y;
        boolean s_ab = (b.x - a.x) * as_y - (b.y - a.y) * as_x > 0;
        if ((c.x - a.x) * as_y - (c.y - a.y) * as_x > 0 == s_ab)
            return false;
        if ((c.x - b.x) * (s.y - b.y) - (c.y - b.y) * (s.x - b.x) > 0 != s_ab)
            return false;
        return true;
    }

    private Point[] getTriangle() {
        // define the triangle shape of this View
        boolean left = alignment == Align.LEFT;
        Point a = new Point(left ? 0 : getWidth(), -1);
        Point b = new Point(left ? 0 : getWidth(), getHeight() + 1);
        Point c = new Point(left ? getWidth() : 0, getHeight() / 2);
        return new Point[] { a, b, c };
    }

}

具有TriangleFrameLayoutroot用户的示例项XML布局可能如下所示:

<?xml version="1.0" encoding="utf-8"?>
<your.package.TriangleFrameLayout 
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/root_triangle"
    android:layout_width="match_parent"
    android:layout_height="160dp"
    android:layout_marginTop="-80dp"
    android:clickable="true"
    android:foreground="?attr/selectableItemBackground">

    <TextView
        android:id="@+id/item_text"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_gravity="center"
        android:padding="20dp"
        android:textSize="30dp"
        android:textStyle="bold"
        android:textColor="#ffffff" />

</your.package.TriangleFrameLayout>

在这里,我们有一个固定的高度160dp,你可以改变你想要的任何东西.重要的是在一半高度的负上边距,-80dp在这种情况下,导致项目重叠和不同的三角形匹配.

现在我们可以膨胀多个这样的项目并将其添加到列表中,即ScrollView.这显示了我们的Activity或Framgent的示例布局:

<?xml version="1.0" encoding="utf-8"?>
<ScrollView xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="match_parent"
    android:layout_height="match_parent">

    <LinearLayout
        android:id="@+id/list"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:orientation="vertical">

    </LinearLayout>

</ScrollView>

以及填充列表的代码:

在这里,我创建了一个虚拟适配器,类似于ListView,它只是枚举从0到15的项目.

    ListAdapter adapter = new BaseAdapter() {
        @Override
        public int getCount() { return 16; }

        @Override
        public Integer getItem(int position) { return position; }

        @Override
        public long getItemId(int position) { return position; }

        @Override
        public View getView(int position, View view, ViewGroup parent) {
            if (view == null) {
                view = getLayoutInflater().inflate(R.layout.item_tria, parent, false);
            }

            // determine whether it's a left or a right triangle
            TriangleFrameLayout.Align align =
                    (position & 1) == 0 ? TriangleFrameLayout.Align.LEFT : TriangleFrameLayout.Align.RIGHT;

            // setup the triangle
            TriangleFrameLayout triangleFrameLayout = (TriangleFrameLayout) view.findViewById(R.id.root_triangle);
            triangleFrameLayout.setTriangleAlignment(align);
            triangleFrameLayout.setBackgroundColor(Color.argb(255, 0, (int) (Math.random() * 256), (int) (Math.random() * 256)));

            // setup the example TextView
            TextView textView = (TextView) view.findViewById(R.id.item_text);
            textView.setText(getItem(position).toString());
            textView.setGravity((position & 1) == 0 ? Gravity.LEFT : Gravity.RIGHT);

            return view;
        }
    };

    // populate the list
    LinearLayout list = (LinearLayout) findViewById(R.id.list);
    for (int i = 0; i < adapter.getCount(); ++i) {
        final int position = i;
        // generate the item View
        View item = adapter.getView(position, null, list);
        list.addView(item);
        item.setOnClickListener(new View.OnClickListener() {
            public void onClick(View v) {
                Toast.makeText(v.getContext(), "#" + position, Toast.LENGTH_SHORT).show();
            }
        });
    }

最后,我们得到一个如下所示的结果:

Answer 2

一行列表中的两项,并使文本可单击.

• 为每个行设计图像,为一个项目设计两个图像.
• 对于每个选项,只使两个项目的文本可单击.