Pat*_*ani 1 mysql count self-join left-join
想要按年份,类型和按月计算
这是我的user table:
id type uname date_created
1 fac a 2015-12-28 17:11:19
2 cs b 2015-12-23 19:09:51
3 cs c 2015-12-23 19:09:21
4 stu d 2015-12-31 18:12:41
5 fac e 2015-11-11 00:00:00
6 fac f 2015-10-07 00:00:00
Run Code Online (Sandbox Code Playgroud)
预期结果:
fac stu cs
1 1 2 // month january
1 0 0 // month octomber
1 0 0 // month november
Run Code Online (Sandbox Code Playgroud)
我尝试的是:
SELECT count(u1.id) as fac, count(u2.id) as stu, count(u3.id) as cs
FROM user u
left join user u1 ON u1.faculty = 'yes' AND YEAR(u1.date_created) = 2015
left join user u2 ON u2.faculty = 'no' AND YEAR(u2.date_created) = 2015
left join user u3 ON u3.faculty = 'club_student' AND YEAR(u3.date_created) = 2015
GROUP BY MONTH(u.date_created) ORDER BY MONTH(u.date_created)
Run Code Online (Sandbox Code Playgroud)
给我错误的结果如:
fac stu cs
6 6 6
6 6 6
24 24 24
Run Code Online (Sandbox Code Playgroud)
您需要的是一个PIVOT将行转换为列的命令.实际上,MySQL不支持这种操作,所以我们需要手动执行它CASE WHEN(参见SQLFiddle):
select
month(date_created) as month,
count(case when faculty = 'yes' THEN 1 END) as fac,
count(case when faculty = 'no' THEN 1 END) as stu,
count(case when faculty = 'club_student' THEN 1 END) as cs
from user
where 1=1
and date_created >= STR_TO_DATE('01-01-2015','%d-%m-%Y')
and date_created < STR_TO_DATE('01-01-2016','%d-%m-%Y')
group by month(date_created)
order by month(date_created)
Run Code Online (Sandbox Code Playgroud)
实际上,你的连接语法没有意义...你连接三次来计算每个表中的id ...从左连接开始,只有当连接匹配时才会返回这些表中的数据,如果不匹配则返回null ...在COUNT聚合函数中不计算空值,因此可以将连接语法简化为INNER连接语法.但是,INNER当您加入相同的表时,甚至不需要连接,并且实际上并不将FROM表中的任何列与表关联JOIN.
这样,您定义的过滤器可以简化为WHERE过滤器和CASE WHEN过滤器,如我所提议的那样.