B.B*_*dan 1 c# linq select casting
我有一个ObservableCollection就是MobileList类型MobileModel.MobileModel有一个List of MobileModelInfo.
我只需要MobileModelInfo那个MobileList.所以我在方法中使用了Linq Select Statement ExtractFirstMobileList().但是我无法分配List,它显示错误.
我的C#源代码:
public class Mobile
{
private ObservableCollection<MobileModel> _mobileList;
public ObservableCollection<MobileModel> MobileList
{
get { return _mobileList; }
set { _mobileList = value; OnPropertyChanged(); }
}
public void GetMobile()
{
List<MobileModel> mList = new List<MobileModel>();
List<MobileModelInfo> modList = new List<MobileModelInfo>();
MobileModel mob = new MobileModel();
modList.Clear();
mob.Brand = "Apple";
modList.Add(new MobileModelInfo { Name = "iPhone 4", Catagory = "Smart Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "iPhone 5", Catagory = "Smart Phone", Year = "2013" });
modList.Add(new MobileModelInfo { Name = "iPhone 6", Catagory = "Premium Smart Phone", Year = "2015" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "IOS";
mList.Add(mob);
mob = new MobileModel();
modList.Clear();
mob.Brand = "Samsung";
modList.Add(new MobileModelInfo { Name = "S4", Catagory = "Smart Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "S5", Catagory = "Smart Phone", Year = "2013" });
modList.Add(new MobileModelInfo { Name = "S6", Catagory = "Ultra Smart Phone", Year = "2015" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "Android";
mList.Add(mob);
mob = new MobileModel();
modList.Clear();
mob.Brand = "MicroSoft";
modList.Add(new MobileModelInfo { Name = "Lumina 9900", Catagory = "Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "Opera X220", Catagory = "Smart Phone", Year = "2013" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "Windows";
mList.Add(mob);
mob = new MobileModel();
modList.Clear();
mob.Brand = "Sony Ericssion";
modList.Add(new MobileModelInfo { Name = "S4", Catagory = "Smart Phone", Year = "2011" });
modList.Add(new MobileModelInfo { Name = "S5", Catagory = "Smart Phone", Year = "2013" });
modList.Add(new MobileModelInfo { Name = "S6", Catagory = "Ultra Smart Phone", Year = "2015" });
mob.Model = new ObservableCollection<MobileModelInfo>(modList);
mob.OS = "Android";
mList.Add(mob);
MobileList = new ObservableCollection<MobileModel>(mList);
ExtractFirstMobileList(MobileList);
}
public void ExtractFirstMobileList(ObservableCollection<MobileModel> Source)
{
List<MobileModelInfo> mInfo = Source.Select(t=> t.Model);
}
}
public class MobileModel : Notify
{
private string _brand = string.Empty;
private List<MobileModelInfo> _model = new List<MobileModelInfo>();
private string _os = string.Empty;
public string Brand
{
get { return _brand; }
set { _brand = value; OnPropertyChanged(); }
}
public List<MobileModelInfo> Model
{
get { return _model; }
set { _model = value; OnPropertyChanged(); }
}
public string OS
{
get { return _os; }
set { _os = value; OnPropertyChanged(); }
}
}
public class MobileModelInfo
{
public string Name { get; set; }
public string Catagory { get; set; }
public string Year { get; set; }
}
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请帮助我如何将Enumerable转换为首选类型.
如果您想创建一个包含所有不同的展平列表,MobileModelInfo您可以使用SelectMany:
List<MobileModelInfo> mInfo = Source.SelectMany(t => t.Model).ToList();
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但是调用了你的方法ExtractFirstMobileList,这表明你想要每个子列表中的第一个项目 - 在这种情况下你可以使用:
List<MobileModelInfo> mInfo = Source.Select(t => t.Model.First()).ToList();
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希望这可以帮助
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