Ste*_*hen 2 iphone xcode uiimageview
我有以下代码:
- (void)viewDidLoad {
NSString *homeDirectoryPath = NSHomeDirectory();
NSString *imagePath = [homeDirectoryPath stringByAppendingString:@"/graph.png"];
NSLog(@"Image: %@", imagePath);
if (![[NSFileManager defaultManager] fileExistsAtPath:imagePath isDirectory:NULL])
{
graph = imagePath;
//[[NSFileManager defaultManager] createDirectoryAtPath:imagePath attributes:nil];
}
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'graph'被定义为UIImageView.我正在尝试在路径'imagePath'中显示该文件.我知道代码graph = imagePath不正确,因为变量'imagePath'表明它包含图像的路径.
如何在特定图像路径上显示我的图像?
问候,斯蒂芬
您必须创建一个imageview对象,将其设置为图像视图的图像并释放您创建的图像:
UIImage *graphImage = [[UIImage alloc] initWithContentsOfFile: imagePath];
graph.image = graphImage;
[graphImage release];
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