Ava*_*is 6 python django django-templates
我将 4 个相同长度的列表和列表的长度传递给我的模板。如何遍历列表?
视图.py
def allbooks(request):
ID = [1,2]
bookName = ["Python", "Java"]
author = ["idk", "who"]
copies = [3,7]
return render(request, 'allbooks.html',{'ID':ID,'bookName':bookName, 'author':author, 'copies':copies,'range':range(len(ID))})
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全书.html
{% extends 'base.html' %}
{% block content %}
{% if user.is_authenticated %}
<div>
<h3>
List of books:
</h3>
<table class="table">
<thead>
<tr>
<th>ID</th>
<th>Book Name</th>
<th>Author</th>
<th>Number of copies</th>
</tr>
</thead>
<tbody>
{% for x in range %}
<tr>
<td>{{id[x]}}</td>
<td>{{bookName[x]}}</td>
<td>{{author[x]}}</td>
<td>{{copies[x]}}</td>
</tr>
{% endfor %}
</tbody>
</table>
</div>
{% else %}
<h3>You must login to continue.</h3>
{% endif %}
{% endblock %}
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我试过用 {% forloop.counter0 %} 替换变量 x 但无济于事。我怎样才能解决这个问题?
Big*_*her 12
将所有列表压缩到一个元组列表中:
books= zip(ID, bookName, author, copies)
return render(request, 'allbooks.html',{ "books": books} )
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比在模板中循环它,如:
{% for book in books %}
<tr>
<td>{{ book.0 }}</td>
<td>{{ book.1 }}</td>
<td>{{ book.2 }} </td>
<td>{{ book.3 }}</td>
</tr>
{% endfor %}
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我为您的图书信息建议了一个更好的结构:
books = [
{ "id":1, "name": "Python", "author":"idk", "copies": 1},
{ "id":2, "name": "Java", "author":"idk2", "copies": 3}
]
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而不是遍历它:
{% for book in books %}
<tr>
<td>{{ book.id }}</td>
<td>{{ book.name }}</td>
<td>{{ book.author }} </td>
<td>{{ book.copies }}</td>
</tr>
{% endfor %}
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