汇总数据并获得总和和计数

Question

我在python中有一个有很多行的对象:

输入:

    Team1     Player1     idTrip13     133
    Team2     Player333   idTrip10     18373
    Team3     Player22    idTrip12     17338899
    Team2     Player293   idTrip02     17656
    Team3     Player20    idTrip11     1883
    Team1     Player1     idTrip19     19393

我需要聚合这些数据(如数据透视表).

OUTPUT我正在努力:

Team1   Player1 : 2 trips : sum(133+19393)
Team2   Player333 : 1 trip : 18373; Player293 : 1 trip : 17656
Team3   Player22 : 1 trip : 17338899; Player20 : 1 trip : 1883

有人可以建议在Python中使用适当的对象,以便我可以有以下输出吗？

print team, player, trips, time

Answer 1

对groupand函数使用pandas DataFrames

1. 将数据放入列表列表中,每个内部列表将是数据帧中的一行.

   In[1]:
   
   mydata = [['Team1', 'Player1', 'idTrip13', 133], ['Team2', 'Player333', 'idTrip10', 18373],
   ['Team3', 'Player22', 'idTrip12', 17338899], ['Team2', 'Player293','idTrip02', 17656], 
   ['Team3', 'Player20', 'idTrip11', 1883], ['Team1', 'Player1', 'idTrip19', 19393]]
   
   df = pd.DataFrame(mydata, columns = ['team', 'player', 'trips', 'time'])
   
   df
   Out[1]:
        team    player       trips      time
   0   Team1   Player1     idTrip13    133
   1   Team2   Player333   idTrip10    18373
   2   Team3   Player22    idTrip12    17338899
   3   Team2   Player293   idTrip02    17656
   4   Team3   Player20    idTrip11    1883
   5   Team1   Player1     idTrip19    19393
   

2. 调用groupby(),传递您希望用作石斑鱼的列,并将功能应用于组.

例子

防爆.1查找每个团队进行的旅行次数.team是石斑鱼,我们count()在柱上应用函数['trips'].

In[2]:
trip_count = df.groupby(by = ['team'])['trips'].count() 

trip_count              
Out[2]:          

 team
Team1    2
Team2    2
Team3    2
Name: trips, dtype: int64

防爆.2(多列):查找团队中每位玩家所花费的总时间.我们使用2列['team', 'player']作为石斑鱼,并sum()在列上应用该功能['time'].

In[3]:              
trip_time = df.groupby(by = ['team', 'player'])['time'].sum() 

trip_time        
Out[3]:

 team   player   
Team1  Player1         19526
Team2  Player293       17656
       Player333       18373
Team3  Player20         1883
       Player22     17338899
Name: time, dtype: int64

防爆.3 (多种功能):对于团队中的每个玩家,查找旅行总次数和旅行总时间.

player_total = df.groupby(by = ['team', 'player']).agg({'time' : 'sum', 'trips' : 'count'})

player_total
Out[4]:
                 trips  time
team    player      
Team1   Player1     2   19526
Team2   Player293   1   17656
        Player333   1   18373
Team3   Player20    1   1883
        Player22    1   17338899