使用Mockito时避免未经检查的警告

Question

我想在调用方法时模拟调用on ScheduledExecutorService来返回ScheduledFuture类的mock schedule.以下代码编译并正常工作:

    ScheduledExecutorService executor = Mockito.mock(ScheduledExecutorService.class);
    ScheduledFuture future = Mockito.mock(ScheduledFuture.class);
    Mockito.when(executor.schedule(
        Mockito.any(Runnable.class),
        Mockito.anyLong(),
        Mockito.any(TimeUnit.class))
    ).thenReturn(future); // <-- warning here

除了我在最后一行得到未经检查的警告:

found raw type: java.util.concurrent.ScheduledFuture
  missing type arguments for generic class java.util.concurrent.ScheduledFuture<V>

 unchecked method invocation: method thenReturn in interface org.mockito.stubbing.OngoingStubbing is applied to given types
  required: T
  found: java.util.concurrent.ScheduledFuture

unchecked conversion
  required: T
  found:    java.util.concurrent.ScheduledFuture

是否有可能以某种方式避免这些警告？

代码就像ScheduledFuture<?> future = Mockito.mock(ScheduledFuture.class);不编译.

Answer 1

当使用替代的模拟规范方法时,所有警告都会消失:

    ScheduledFuture<?> future = Mockito.mock(ScheduledFuture.class);
    Mockito.doReturn(future).when(executor).schedule(
        Mockito.any(Runnable.class),
        Mockito.anyLong(),
        Mockito.any(TimeUnit.class)
    );