MAN*_*624 4 python beautifulsoup python-3.x python-requests
我想要做的是从邮政编码中检索城市和州.这是我到目前为止所拥有的:
def find_city(zip_code):
zip_code = str(zip_code)
url = 'http://www.unitedstateszipcodes.org/' + zip_code
source_code = requests.get(url)
plain_text = source_code.text
index = plain_text.find(">")
soup = BeautifulSoup(plain_text, "lxml")
stuff = soup.findAll('div', {'class': 'col-xs-12 col-sm-6 col-md-12'})
我也尝试使用id ="zip-links",但这不起作用.但事情就是这样:当我跑步时,print(plain_text)我得到以下内容:
<!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN">
<html><head>
<title>403 Forbidden</title>
</head><body>
<h1>Forbidden</h1>
<p>You don't have permission to access /80123
on this server.<br />
</p>
</body></html>
所以我想我的问题是:是否有更好的方法从邮政编码获得城市和州？或者有一个原因,unitedstateszipcodes.gov不合作.毕竟,很容易看到源,标签和文本.谢谢
您需要添加用户代理:
headers = {"User-agent":"Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.80 Safari/537.36"}
def find_city(zip_code):
zip_code = str(zip_code)
url = 'http://www.unitedstateszipcodes.org/' + zip_code
source_code = requests.get(url,headers=headers)
完成后,响应为200,您将获得源:
In [8]: url = 'http://www.unitedstateszipcodes.org/54115'
In [9]: headers = {"User-agent":"Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.80 Safari/537.36"}
In [10]: url = 'http://www.unitedstateszipcodes.org/54115'
In [11]: source_code = requests.get(url,headers=headers)
In [12]: source_code.status_code
Out[12]: 200
如果您想要详细信息,可以轻松解析:
In [59]: soup = BeautifulSoup(plain_text, "lxml")
In [60]: soup.find('div', id='zip-links').h3.text
Out[60]: 'ZIP Code: 54115'
In [61]: soup.find('div', id='zip-links').h3.next_sibling.strip()
Out[61]: 'De Pere, WI 54115'
In [62]: url = 'http://www.unitedstateszipcodes.org/90210'
In [63]: source_code = requests.get(url,headers=headers).text
In [64]: soup = BeautifulSoup(source_code, "lxml")
In [65]: soup.find('div', id='zip-links').h3.text
Out[66]: 'ZIP Code: 90210'
In [70]: soup.find('div', id='zip-links').h3.next_sibling.strip()
Out[70]: 'Beverly Hills, CA 90210'
您还可以将每个结果存储在数据库中,并首先尝试在数据库中进行查找.
我认为你正在走更长的路来解决一个简单的问题！
尝试使用pyzipcode
>>> from pyzipcode import ZipCodeDatabase
>>> zcdb = ZipCodeDatabase()
>>> zipcode = zcdb[54115]
>>> zipcode.zip
u'54115'
>>> zipcode.city
u'De Pere'
>>> zipcode.state
u'WI'
>>> zipcode.longitude
-88.078959999999995
>>> zipcode.latitude
44.42042
>>> zipcode.timezone
-6
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