Bol*_*olo 24 string character ios swift
我有一个包含二进制数字的字符串.如何将其分成数字对?
假设字符串是:
let x = "11231245"
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我想在每2个字符后面添加一个分隔符,例如":"(即冒号).
我希望输出为:
"11:23:12:45"
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我怎么能在Swift中这样做?
Leo*_*bus 54
Swift 4.2•Xcode 10
extension Collection {
var pairs: [SubSequence] {
var startIndex = self.startIndex
let count = self.count
let n = count/2 + count % 2
return (0..<n).map { _ in
let endIndex = index(startIndex, offsetBy: 2, limitedBy: self.endIndex) ?? self.endIndex
defer { startIndex = endIndex }
return self[startIndex..<endIndex]
}
}
}
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extension Collection {
func distance(to index: Index) -> Int { distance(from: startIndex, to: index) }
}
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测试
extension StringProtocol where Self: RangeReplaceableCollection {
mutating func insert<S: StringProtocol>(separator: S, every n: Int) {
for index in indices.dropFirst().reversed()
where distance(to: index).isMultiple(of: n) {
insert(contentsOf: separator, at: index)
}
}
func inserting<S: StringProtocol>(separator: S, every n: Int) -> Self {
var string = self
string.insert(separator: separator, every: n)
return string
}
}
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Sté*_*uca 16
我会选择这个紧凑的解决方案(在Swift 4中):
let s = "11231245"
let r = String(s.enumerated().map { $0 > 0 && $0 % 2 == 0 ? [":", $1] : [$1]}.joined())
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您可以进行扩展并参数化步幅和分隔符,以便您可以将它用于您想要的每个值(在我的情况下,我使用它来转储32位空间操作的十六进制数据):
extension String {
func separate(every stride: Int = 4, with separator: Character = " ") -> String {
return String(enumerated().map { $0 > 0 && $0 % stride == 0 ? [separator, $1] : [$1]}.joined())
}
}
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在您的情况下,这给出了以下结果:
let x = "11231245"
print (x.separate(every:2, with: ":")
$ 11:23:12:45
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Joe*_*her 10
简短而简单,let如果你愿意,可以添加一两个
extension String {
func separate(every: Int, with separator: String) -> String {
return String(stride(from: 0, to: Array(self).count, by: every).map {
Array(Array(self)[$0..<min($0 + every, Array(self).count)])
}.joined(separator: separator))
}
}
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let a = "separatemepleaseandthankyou".separate(every: 4, with: " ")
a 是
分开mepl轻松和你
斯威夫特 5.3
/// Adds a separator at every N characters
/// - Parameters:
/// - separator: the String value to be inserted, to separate the groups. Default is " " - one space.
/// - stride: the number of characters in the group, before a separator is inserted. Default is 4.
/// - Returns: Returns a String which includes a `separator` String at every `stride` number of characters.
func separated(by separator: String = " ", stride: Int = 4) -> String {
return enumerated().map { $0.isMultiple(of: stride) && ($0 != 0) ? "\(separator)\($1)" : String($1) }.joined()
}
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我对该代码的尝试将是:
func insert(seperator: String, afterEveryXChars: Int, intoString: String) -> String {
var output = ""
intoString.characters.enumerate().forEach { index, c in
if index % afterEveryXChars == 0 && index > 0 {
output += seperator
}
output.append(c)
}
return output
}
insert(":", afterEveryXChars: 2, intoString: "11231245")
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哪个输出
11:23:12:45
let y = String(
x.characters.enumerate().map() {
$0.index % 2 == 0 ? [$0.element] : [$0.element, ":"]
}.flatten()
)
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小智 7
它是我的代码迅速4
let x = "11231245"
var newText = String()
for (index, character) in x.enumerated() {
if index != 0 && index % 2 == 0 {
newText.append(":")
}
newText.append(String(character))
}
print(newText)
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输出11:23:12:45
小智 6
用于插入分隔符的简单一行代码(Swift 4.2):-
let testString = "123456789"
let ansTest = testString.enumerated().compactMap({ ($0 > 0) && ($0 % 2 == 0) ? ":\($1)" : "\($1)" }).joined() ?? ""
print(ansTest) // 12:34:56:78:9
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斯威夫特 4.2.1 - Xcode 10.1
extension String {
func insertSeparator(_ separatorString: String, atEvery n: Int) -> String {
guard 0 < n else { return self }
return self.enumerated().map({String($0.element) + (($0.offset != self.count - 1 && $0.offset % n == n - 1) ? "\(separatorString)" : "")}).joined()
}
mutating func insertedSeparator(_ separatorString: String, atEvery n: Int) {
self = insertSeparator(separatorString, atEvery: n)
}
}
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用法
let testString = "11231245"
let test1 = testString.insertSeparator(":", atEvery: 2)
print(test1) // 11:23:12:45
var test2 = testString
test2.insertedSeparator(",", atEvery: 3)
print(test2) // 112,312,45
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