在PHP预处理语句中插入日期

Question

我试图在准备好的语句中将当前日期(在dmY中)插入到mysql表中.我无法正确使用代码.我在php中调用当前日期

$dat = date("d-m-Y");

然后包括在这样的准备好的声明中

$stmt = $mysqli->prepare("INSERT INTO mytable (name, date) VALUES (?, ?)");
$stmt->bind_param('ss', $name, $dat);
$reslt = $stmt->execute();

在表中,日期未插入.它仍然是EA.我怎么能纠正这个？

Answer 1

您应该使用YYYY-MM-DD格式:

$dat = date("Y-m-d");

Answer 2

尝试这样的事情..

$stmt = $mysqli->prepare('insert into foo (dt) values (?)');
$dt = '2009-04-30 10:09:00';
$stmt->bind_param('s', $dt);
$stmt->execute();

否则这个..

global $dbh;
$query = "INSERT INTO loan (title, description, start_date, end_date) VALUES (?,?,?,?)"

$statement = $dbh->prepare($query);
$statement->bind_param("ssss", $title,$description,$startDate,$endDate);

$statement->execute();
print $statement->error; //to check errors
$statement->close();