如何在ajax调用中传递特殊字符变量i并在spring控制器中获取值。如果文件name="##@jsuduu"
function deleeteimg(){
var filename=$("#filenm").text();
alert(filename);
//var filename=$(this).attr("data-id");
var url="/myuploads/deleteFile.html?filename="filename;
$.ajax({
type: "GET",
url: url,
contentType: 'html',
success: function(response) {
window.location.href="/myuploads/showUploads.html";
}
});
}
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小智 6
使用以下方法有效
encodeURI()
encodeURIComponent()
type: "POST",
url: "ajax/save",
data:"Name="+encodeURIComponent("##@jsuduu")
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