我正在尝试检查我的数据库中是否存在用户,然后为用户执行一些验证过程,如果没有返回入侵者消息.我正在使用Java和MySQL来达到这个目的.这是我的代码.
public class Check{
public boolean isPresent(){
connect();// private method that connects to db
boolean isAvailable = false;
String query = "SELECT EXISTS(SELECT 1 FROM students WHERE matric =" + this.myId + ")"; // this.myId has been passed into the constructor
try{
Statement statement;
ResultSet resultSet;
statement = connection.createStatement();
resultSet = statement.executeQuery(query);
if(resultSet.absolute(1)){
isAvailable = true;
}else{
isAvailable = false;
}catch(SQLException e){
e.printStackTrace();
}finally{
closeConnection();// private method that closes connection
return isAvailable;
}
}
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我已经检查过这样的解决方案,但似乎没有解决这个问题.我得到的错误是:"where子句中的未知列CCE",JDBC API中还有其他错误.在我看来,就像我从传承人那里传来的价值一样,有些东西被截断了.
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'CCE' in 'where clause'
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:400)
at com.mysql.jdbc.Util.getInstance(Util.java:383)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:980)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3847)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3783)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2447)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2594)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2541)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2499)
at com.mysql.jdbc.StatementImpl.executeQuery(StatementImpl.java:1432)
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从简易修复到正确
1 - 引用您的ID将修复您的SQL错误(添加'around id)
String query = "SELECT EXISTS(SELECT 1 FROM students WHERE matric = '" + this.myId + "')"; // this.myId has been passed into the constructor
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但是,仍然使用子选择存在?为什么不直接让学生?
2 - 删除子选择
String query = "SELECT * FROM students WHERE matric = '" + this.myId + "'";
try{
Statement statement;
ResultSet resultSet;
statement = connection.createStatement();
resultSet = statement.executeQuery(query);
if(resultSet.next()){
isAvailable = true;
}else{
isAvailable = false;
} //Missing in your code
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想想my ...就像... myId = "killer'); DROP TABLE STUDENTS; --"- 你不想这样执行.
String query = "SELECT * FROM students WHERE matric = ?";
try{
PreparedStatement statement;
ResultSet resultSet;
statement = connection.prepareStatement(query);
statement.setString(1, myId);
resultSet = statement.executeQuery();
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通过使用try-with-resource,您可以摆脱大多数捕获:
String query = "SELECT * FROM students WHERE matric = ?";
try (PreparedStatement statement = connection.prepareStatement(query)) {
statement.setString(1, myId);
try(ResultSet resultSet = statement.executeQuery()) {
return rs.next();
}
} catch(SQLException se) {
se.printStackTrace();
return false;
}
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