将char指针数组传递给函数

Question

我正在尝试将初始化的char指针数组传递给函数.我似乎无法弄清楚为什么函数只会打印出数组中每个元素的数字.

有谁知道如何从传入的指针数组中打印每个字符串元素？

#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>

void sort(char *);

int main()
{
   char *states[4] = {"Florida", "Oregon", "California", "Georgia"};

   sort(*states);

   return 0;
}

void sort(char *states)
{
   int x;

   for (x = 0; x < 4; x++) {
      printf("\nState: %d\n", states[x]); //only this will compile
      //printf("\nState: %s\n", states[x]); //need to print this.
   }

}

Answer 1

你sort如果要打印数组的内容函数必须接受指针数组.

void sort (char *states[], size_t num_states) {
    int x;

    for (x = 0; x < num_states; ++x) {
        printf("\nState: %s\n", states[x]); /* Note %s instead of %d */
    }
}

而且,您必须将数组传递给函数.

sort(states, 4);