Tri*_*ion 5 python numpy slice
切片的索引slice(start, stop[, step])通常可以表示为range(start, stop, step)(或者range(*slice(start, stop, step).indices(length))在考虑基础维度时).
假设我有两个多维切片,第二个切片可以用作应用第一个切片的结果的切片.
例:
import numpy as np
data = np.random.rand(*(100, 100, 100))
a = data[::2, 7, :] # slice 1, a.shape = (50,100)
b = a[1, ::-1] # slice 2, b.shape = (100,)
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我想找到一个用于计算执行相同工作的单个切片的通用表达式.我知道底层数据结构的维度.
c = data[2, 7, ::-1] # same as b
np.array_equal(b, c) # True
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所以,从获得[::2, 7, :]并[1, ::-1]以[2, 7, ::-1] 在这个例子中,我需要像一个函数:
def concatenate_slices(shape, outer_slice, inner_slice):
...
return combined_slice
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哪里outer_slice和inner_slice都将成为切片的元组.在示例shape=(100, 100, 100)和outer_slice=(slice(None, None, 2), 7, slice(None, None, None))和inner_slice=(1, slice(None, None, -1)).
我不确定如何有效地做到这一点.
__getitem__(slice)调用时我的对象做了一些事情(没有中间视图),我想只做一次,但仍然有可能有片切片.
作为扩展(可选)我想知道如果切片中有椭圆会发生什么.我怎样才能组合起来呢?
让我们从简单的情况开始:一维数组。我们需要跟踪最终切片的start、stop和值,我们可以像这样更新:step
def update_1d(a, b, length):
a_start, a_stop, a_step = a.indices(length)
a_length = len(xrange(a_start, a_stop, a_step))
if a_length == 0:
# doesn't matter what b is if data[a] is []
return a
b_start, b_stop, b_step = b.indices(a_length)
b_length = len(xrange(b_start, b_stop, b_step))
if b_length == 0:
# result will be empty, so we can exit early
return slice(0, 0, 1)
# convert b's start into a's coordinates, without wrapping around
start = max(0, a_start + b_start * a_step)
# steps are multiplicative, which makes things easy
step = a_step * b_step
# the stop index is the hard part because it depends on the sign of both steps
x = a_start + b_stop * a_step
if step < 0:
# indexing backwards, so truncate if b's converted step goes below zero
stop = x if x >= 0 else None
elif a_step > 0:
# both steps are positive, so take the smallest stop index
stop = min(a_stop, x)
else:
# both steps are negative, so take the largest stop index
stop = max(a_stop, x)
return slice(start, stop, step)
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请注意,这期望a并且b是切片。不过,您通常可以将其他形式转换为切片对象。这甚至包括Ellipsis物体,假设你知道你有多少个维度。
为了将其扩展到多维情况,我们需要做一些簿记来跟踪哪个原始维度被切片。例如,如果有data[::2, 7, :][:, 2:-2],则必须将第二个切片的第二个维度映射到第一个切片的第三个维度。
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